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Gemiola [76]
3 years ago
10

What is the circumference of the circle use 3.24 for pi

Mathematics
1 answer:
never [62]3 years ago
5 0

Step-by-step explanation:

Formula:

d×3.14=C

or

r×3.14×2=C

d=diameter

r=radius

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Step-by-step explanation:

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What is 3 3/5 ÷ 1 4/5 =
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The library has thirteen
dybincka [34]

Answer:

If the shelves  are 4/5 full, then the total number of books in the library is 1,040 books

Step-by-step explanation:

13 roll of bookcases

All the bookcases have four shelves

Total number of shelves = 4 x 13

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If the shelves  are 4/5 full, then the total number of books in the library is,

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2 years ago
What is the value of 36x-8y^2 when x=3 and y= -6?
Zepler [3.9K]

Answer:

-6 gets canceled out because it gets squared. When you square a number, you multiply it by itself. Any negative number times a negative number results in a positive number. So instead of -36 its just 36

7 0
2 years ago
What is the largest possible integral value in the domain of the real-valued function
kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

<u>Algebra I</u>

  • Domain is the set of x-values that can be inputted into function f(x)

<u>Calculus</u>

  • Antiderivatives
  • Integral Property: \int {cf(x)} \, dx = c\int {f(x)} \, dx
  • Integration Method: U-Substitution
  • [Integration] Reverse Power Rule: \int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = \frac{1}{\sqrt{800-2x} }

<u>Step 2: Identify Variables</u>

<em>Using U-Substitution, we set variables in order to integrate.</em>

u = 800-2x\\du = -2dx

<u>Step 3: Integrate</u>

  1. Define:                                                                                                            \int {f(x)} \, dx
  2. Substitute:                                                                                         \int {\frac{1}{\sqrt{800-2x} } } \, dx
  3. [Integral] Int Property:                                                                                     -\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx
  4. [Integral] U-Sub:                                                                                           -\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du
  5. [Integral] Rewrite:                                                                                          -\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du
  6. [Integral - Evaluate] Reverse Power Rule:                                                 -\frac{1}{2}(2\sqrt{u}) + C
  7. Simplify:                                                                                                         -\sqrt{u} + C
  8. Back-Substitute:                                                                                            -\sqrt{800-2x} + C
  9. Factor:                                                                                                           -\sqrt{-2(x - 400)} + C

<u>Step 4: Identify Domain</u>

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

7 0
3 years ago
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