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stepladder [879]

3 years ago

11

A game Room has a floor that is 120ft by 75ft. A scale drawing of the floor on grid paper uses a scale of one unit : 5 feet. Wha

t are the dimensions of the scale drawing ?

1 answer:

nika2105 [10]3 years ago

5 0

24 units by 15 units. divide both numbers by 5

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Find a polynomial function with real coefficients that has zeros-3, 2i

Jlenok [28]

Check google it might have it

8 0

3 years ago

I need help with this question

Novay_Z [31]

Answer:

$\frac{\sqrt{3} - 1}{2\sqrt{2}}$

$\frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

$- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$

Step-by-step explanation:

Given $\frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6}$

(A) $sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4} + \frac{\pi}{6})$

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2}$

$$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}$

(B) Cos(A + B) = CosAcosB - SinASinB

$cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}})$

$\implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2}$

$\implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6})$

$$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

(C) Tan(A + B) = $\frac{Sin(A +B)}{Cos(A + B)}$

From the above obtained values this can be calculated and the value is $- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$ .

3 0

3 years ago

Match each statement (term) with its value in relation to 0 (definition). Match Term Definition A building is 38 feet tall. A) –

Kitty [74]

The answer is C. The rest of the answers make no sense and do not work.

7 0

3 years ago

Read 2 more answers

A corporate team-building event costs $1, plus an additional $1 per attendee. How many

andrey2020 [161]

Answer:

9 attendees

Step-by-step explanation:

1+4=5

46/5=9 R1 the slash is dividing it hope it help's

3 0

3 years ago

((-2,3) and (4,7)<br> what is the distance of this

strojnjashka [21]

Answer:

Step-by-step explanation:

(-2, 3 ) ; (4 , 7)

Distance = $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

$=\sqrt{(4-[-2])^{2}+(7-3)^{2}}\\\\=\sqrt{(4+2)^{2}+(7-3)^{2}}\\\\=\sqrt{6^{2}+4^{2}}\\\\=\sqrt{36+16}\\\\=\sqrt{52}\\\\=\sqrt{2*2*13}\\\\=2\sqrt{13}$

7 0

3 years ago