Answer: 
-3 times the square root of 5
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Explanation:
Let 
Replace all the root 5 terms with x and we go from

to

From here, combine like terms to get

and the last thing to do is replace the x with sqrt(5)

Meaning that,


Answer:
Step-by-step explanation:
Area of a square
Area = l*l
121=l^2
l=√121
L=11cm
Volume=length*width*height
V=2*2*2 or V+2^3
V=8
The volume of the display is 8 cubic feet
Hi !
<em></em>
<em></em>
<em>Which two techniques are used in constructions with paper folding?</em>
A. Drawing arcs
C. Folding the tracing paper
Answer:

<em>Answer is </em><em>given below with explanations</em><em>. </em>
Step-by-step explanation:

<em>HAVE A NICE DAY</em><em>!</em>
<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>.</em>