Write y=(- 3/4)x+3 in standard form using intregers
1 answer:
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Answer:
Y=4 X= -6 or (-6,4)
Step-by-step explanation:
Okay so
3x+10y=22
-3x-8y=-14
- basically, it's like one big equation. First, subtract 3x from -3x which cancels out and gives us 0
- 10y minus 8y gives us 2y.
- 22 minus 14 gives us 8
3x+10y=22
<u>-3x-8y=-14</u>
0+2y=8
Now that we have this, we can solve for y. in order to do this, we have to divide both sides by 2.
From here we know that y=4 because the 2s cancel out leaving y and 8 divided by 2 is 4.
y= 4
Now we can fill in. You can pick any equation for this but I'm going to chose the first one.
3x+10y=22
we can fill in 4 for y
3x+10(4)=22
3x+40=22
Next we are going to subtract 40 on both sides.
3x+40=22
-40 -40
3x= -18
Next, we're going to divide -18 by 3.
The 3s cancel out leaving us x. -18 divided by 3 is -6.
x= -6
Hope this helped!! :)