This is a sinusoidal wave with an <u>amplitude of 2</u> , riding on a constant value of 3 . The 3 isn't part of the function's amplitude ... the function wiggles between 2 under it and 2 over it.
The period of the function is the change in 'x' that adds (2 pi) to the angle.
When x=0, the angle is pi
When the angle is (3 pi) . . .
3 pi = 3x + pi 2 pi = 3x x = 2/3 pi <u>The period of the function is 2/3 pi </u>.
When x=0, the function is cos(pi) rather than cos(0). So the function is a cosine with a <u>phase shift of +pi</u>. It could also be described as a sine with a phase shift of -pi/2 or +3pi/2 .
Uhhhh I don't think that the correct answer. First, find the gradient of the line segment. Gradient = Rise/Run = (2-6)/(2-5) = 4/3. Since the other line segment is parallel to this line segment, their gradients are the same. That means (-2+4)/(x-5) = 4/3. 2/(x-5) = 4/3 It is obvious x = 6.5
