(2c) Solve the equation: 6 = 1/2z

Mathematics

2 answers:

vesna_86 [32]2 years ago

7 0

Answer:

You move all terms to the left;

6-(1/2z)=0

Domain of the equation: 2z)!=0

z!=0/1

z!=0

You add all the numbers together, and all the variables;

-(+1/2z)+6=0

You get rid of parentheses;

-1/2z+6=0

You multiply all the terms by the denominator;

6*2z-1=0

You multiply elements;

12z-1=0

You move all terms containing z to the left, all other terms to the right;

12z=1

z=1/12

And your answer is: z=1/12

Step-by-step explanation:

Paul [167]2 years ago

3 0

Answer:

z=12

Step-by-step explanation:

multiply both sides of the equation by 2

12=z

swap the sides of the equation

z=12

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Question 14 of 25What is the complete factorization of the polynomial below?x³+x² + 4x+4O A. (x-1)(x+2)(x+2)B. (x + 1)(x + 2)(x

mote1985 [20]

GIVEN:

We are given the following polynomial;

$x^3+x^2+4x+4$

Required;

We are required to factorize this polynomial completely.

Step-by-step explanation;

To factorize this polynomial, we start by grouping;

$(x^3+x^2)+(4x+4)$

We now take the common factor in each group;

$\begin{gathered} x^2(x+1)+4(x+1) \\ \\ (x^2+4)(x+1) \end{gathered}$

Next, we factorize the first parenthesis. To do this we set the equation equal to zero and solve for x as follows;

$\begin{gathered} x^2+4=0 \\ \\ Subtract\text{ }4\text{ }from\text{ }both\text{ }sides: \\ \\ x^2=-4 \\ \\ Take\text{ }the\text{ }square\text{ }root\text{ }of\text{ }both\text{ }sides: \\ \\ x=\pm\sqrt{-4} \\ \\ x=(\pm\sqrt{-1}\times\sqrt{4}) \\ \\ x=\pm2i \end{gathered}$

Therefore, the factors of the other parenthesis are;