Answer:
1. 155 yd², 2. 379.54 ft², 5. x = 65.82π
Step-by-step explanation:
1. A = (1/2) · (3 + 13) · 8
A = (1/2)(16)(8)
A = 64
A = bh
A = 13*7
A = 91
64 + 91 = 155
155 yd²
2. A = bh
A = 25x25
A = 625
A = πr²
A = 3.14*12.5²
A = 3.14*156.25
A = 490.625
490.925/2 = 245.4625
625 - 245.4625 = 379.5375
379.54 ft²
3. and 4. Sorry, I don't know how to solve these
5. A = πr²
A = 3.14*7²
A = 3.14*49
A = 153.86
x/154 = 153.86π/360
360x = 154*153.86π
360x = 23694.44π
x = 65.8178889π
x = 65.82π
Hope this helps :)
Answer:
this is all I got for u look at my attachment
<u>Answer-</u>
<em>Area of the triangle is </em><em>10 sq.units</em>
<u>Solution-</u>
We know that,
![\text{Area of the triangle}=\dfrac{1}{2}[{x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20the%20triangle%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5B%7Bx_1%28y_2-y_3%29%2Bx_2%28y_3-y_1%29%2Bx_3%28y_1-y_2%29%5D)
Taking,
(x₁, y₁) = (3, 3)
(x₂, y₂) = (3, -1)
(x₃, y₃) = (-2, -5)
Then putting these in the formula,
![\text{Area of the triangle}=\dfrac{1}{2}[3(-1+5)+3(-5-3)-2(3+1)]](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20the%20triangle%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5B3%28-1%2B5%29%2B3%28-5-3%29-2%283%2B1%29%5D)
![=\dfrac{1}{2}[3(4)+3(-8)-2(4)]](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%7D%7B2%7D%5B3%284%29%2B3%28-8%29-2%284%29%5D)
![=\dfrac{1}{2}[12-24-8]](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%7D%7B2%7D%5B12-24-8%5D)
![=\dfrac{1}{2}[-20]](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%7D%7B2%7D%5B-20%5D)
As area can not be negative, ignoring negative sign,
1) the slope of a line is m in the equation y=mx+b, in this case m isn’t there because m=1 so the slope is 1
2) the slope of a perpendicular line of this would be the reciprocal which is -1
