Ok, use the sum of triangle theorm all angles of the triangle has a sum of 180 degrees. B is 90 degrees because it labeled it self ABC the A angle seems by the degree to be at the top of the triangle and there needs to be a 90 degree angle in a right triangle. Now if you add 90 + 28 you get 118 degrees subtract that from the sum of all the angles ( 180 degrees), and get 62 degrees as angle C. Angle A is 28 degrees, angle B is 90 degrees, angle C is 62 degrees.
If s is the side of the square base, the area of the square base is s^2.
The volume of the square base is,
V = (s²) (h)
s² = V/h
s² = 3n³ + 13n² + 16n + 4 / <span>3n + 1
You can do this division by factoring, synthetic division, or by plain division.
Factoring out 3n + 1 from the numerator gives you:
</span>s² = (3n + 1)(n² + 4n + 4) / 3n+1
s² = n² + 4n + 4
Therefore, the area of the square base is <span>n² + 4n + 4.</span>
Answer:
0.44
Step-by-step explanation:
-3x^2 + 2y^2 + 5xy - 2y +5x^2 - 3y^2
Combine like terms
-3x^2 + 5x^2 = 2x^2 2y^2 - 3y^2 = -1y^2
2x^2 - 1y^2 + 5xy - 2y
Now plug in the solutions Note: it is easier if you have all decimals or all fractions (-1/10=-.1
2(0.5)^2 - 1(-0.1)^2 + 5(0.5)(-0.1) - 2(-0.1)
Simplify:
0.5 - 0.01 - 0.25 + 0.2
0.5 + 0.2 - 0.01 - 0.25
0.7 - 0.26
0.44
This could be wrong because I'm going into the fifth grade but wouldn't it just be (7,-3)?
