Let after n week both tanks have same quantity of water .
for first tank
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tank hold 540 gallon of water ,
leaking of water 4 gallon /week
so, in n week water leak from the tank =4× n = 4n
now, after n week quantity of water in the tank = 540 -4n
for second tank
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quantity of water in the tank =720 gallon
leaking of water at the rate = 7gallon/week
so, after n week water leak from the tank = 7× n =7n
after n week quantity of water rest in the tank = 720 -7n
now ,
according to question ,
water in first tank = water in second tank
540 -4n = 720 -7n
7n -4n = 720 -540
3n = 180
n = 60
hence , after 60 week both tank have same quantity of water.
3 fourths of an hour is : (3/4)
(3/4)*4=3 hours
hope this helps!
3 (x + 7) = 5x - 2
3x + 21 = 5x - 2
3x - 5x = -2 - 21
-2x = -23
x = -23/-2
x = 23/2
Answer:
112, 119 and 126.
Step-by-step explanation:
Let the consecutive multiples of 7 be 7n, 7(n+1) and 7(n+2) where n is an integer, then:-
7n + 7n + 7 + 7n + 14 = 357
21n + 21 = 357
21(n + 1) = 357
n = (357/21) - 1
n = 17 + 1 = 16.
So the numbers are 7*16 = 112, 7*17 = 119 and 7*18 = 126.
