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asambeis [7]
3 years ago
12

8 of 10

Mathematics
1 answer:
Naya [18.7K]3 years ago
7 0

Answer:

2.

Step-by-step explanation:

To find the answer, we take Gordon's result, 3, and subtract 2, which is what he added to get 3. This gives us a result of 1. We then multiply by 2, as 1 was the quotient of dividing the original number by 2. This leaves us with an answer of 2.

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A water tank hols 540 galloms but is leaking at a rate of 4 gallons per week a second water tank holds 720 gallons but is leakin
Murrr4er [49]
Let after n week both tanks have same quantity of water .

for first tank
=============
tank hold 540 gallon of water ,
leaking of water 4 gallon /week
so, in n week water leak from the tank =4× n = 4n

now, after n week quantity of water in the tank = 540 -4n

for second tank
==============
quantity of water in the tank =720 gallon
leaking of water at the rate = 7gallon/week
so, after n week water leak from the tank = 7× n =7n

after n week quantity of water rest in the tank = 720 -7n

now ,
according to question ,

water in first tank = water in second tank
540 -4n = 720 -7n

7n -4n = 720 -540

3n = 180

n = 60

hence , after 60 week both tank have same quantity of water.
4 0
3 years ago
What is 7 1 / 5 - 6 2/5
Lunna [17]
7\dfrac{1}{5}=\dfrac{7\cdot5+1}{5}=\dfrac{35+1}{5}=\dfrac{36}{5}\\\\6\dfrac{2}{5}=\dfrac{6\cdot5+2}{5}=\dfrac{30+2}{5}=\dfrac{32}{5}\\\\7\dfrac{1}{5}-6\dfrac{2}{5}=\dfrac{36}{5}-\dfrac{32}{5}=\dfrac{36-32}{5}=\boxed{\dfrac{4}{5}}



7\dfrac{1}{5}-6\dfrac{2}{5}=(7-6)+\left(\dfrac{1}{5}-\dfrac{2}{5}\right)=1+\dfrac{1-2}{5}=1+\dfrac{-1}{5}=1-\dfrac{1}{5}\\\\=\dfrac{5}{5}-\dfrac{1}{5}=\dfrac{5-1}{5}=\boxed{\frac{4}{5}}
4 0
3 years ago
Bruce reads 3fourths hour each night.how long will he read in 4 nights
OlgaM077 [116]
3 fourths of an hour is : (3/4)
(3/4)*4=3 hours

hope this helps!
5 0
3 years ago
Three times the sum of a number and seven is two less than five times the number.
m_a_m_a [10]
3 (x + 7) =  5x - 2
3x + 21 = 5x - 2
3x - 5x = -2 - 21

-2x = -23 
x = -23/-2
x = 23/2


4 0
3 years ago
The sum of three consecutive multiples of 7 is 357.find the smallest multiple.
Afina-wow [57]

Answer:

112, 119 and 126.

Step-by-step explanation:

Let the consecutive  multiples of 7 be 7n, 7(n+1) and 7(n+2)  where n is an integer,  then:-

7n + 7n + 7 + 7n + 14 = 357

21n + 21 = 357

21(n + 1) = 357

n = (357/21) - 1

n = 17 + 1 = 16.

So the numbers are 7*16 = 112, 7*17 = 119 and 7*18 = 126.


3 0
3 years ago
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