BLEM SOLVING

Mathematics

1 answer:

ki77a [65]3 years ago

8 0

The correct answer is 68

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This hyperbola is centered at theorigin. Find its equation.Foci: (-2,0) and (2,0)Vertices: (-1,0) and (1,0)

beks73 [17]

SOLUTION

From the question, the center of the hyperbola is

$\begin{gathered} (h,k),\text{ which is } \\ (0,0) \end{gathered}$

a is the distance between the center to vertex, which is -1 or 1, and

c is the distance between the center to foci, which is -2 or 2.

b is given as

$\begin{gathered} b^2=c^2-a^2 \\ b^2=2^2-1^2 \\ b=\sqrt[]{3} \end{gathered}$

But equation of a hyperbola is given as

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

Substituting the values of a, b, h and k, we have

$\begin{gathered} \frac{(x-0)^2}{1^2}-\frac{(y-0)^2}{\sqrt[]{3}^2}=1 \\ \frac{x^2}{1}-\frac{y^2}{3}=1 \end{gathered}$

Hence the answer is

$\frac{x^2}{1}-\frac{y^2}{3}=1$

5 0

1 year ago

What's -8.2 x 10 to the fifth power? Please explain your answer. Thank you!

Stolb23 [73]

First lets find -8.2 x 10 = -82 know we find 82^5 which is 82*82*82*82*82

-82*-82=6724 and then 6724*-82= -551368 and then -551368*-82 =45212176 and then 45212176*-82= -3707398432 and finally -3707398432 is our answer i checked the calc to after i did the hard math that took me forever i had some help from the calc and i got this hopefully this helps

8 0

3 years ago

A bakery sold a total of 3028 coffee buns and blueberry buns. 1560 more coffee buns were sold than the blueberry buns. How many

Natali [406]

Answer:

$\large{ \tt{ - \: HEY \: AH~\:♡ }}$

$\large{ \tt{✺ \: SOLUTION}} :$

Provided : Total sold bakery items : 3028 coffee buns and blueberry buns & 1560 more coffee buns were sold than the blueberry buns.

To find : Number of coffee buns the bakery sold

- First , Subtract 1560 from 3028 :

$\large{ \tt{→ \: 3028 - 1560 = 1468}}$

We just subtacted the number of more coffee buns from the number of told items sold which means that the number of coffee buns and the number of blueberry buns sold are equal for now. Now divide 1428 by 2 :

$\large{ \tt{→ \frac{1428}{2} = 734 }}$