Please help :( can you explain and write the answer

Mathematics

1 answer:

GrogVix [38]3 years ago

3 0

Answer:

f(x)=x-2

Find the domain by finding where the function is defined. The range is the set of values that correspond with the domain.

Domain: (−∞,∞),x|x ∈R}(-∞,∞),{x|x ∈R}

Range: (−∞,∞),{y|y∈R}

g(x)=x^2-3x+2

Domain: (−∞,∞),{x|x ∈R}(-∞,∞),{x|x ∈R}

Range: [−1/4,∞),{y∣y≥−1/4}

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Find an equation of the line through these points (15,2.2) (5,1.6). Write answer in a slope-intercept form

nadya68 [22]

Answer:

$y=\frac{\displaystyle 3}{\displaystyle 50}x+\frac{\displaystyle 13}{\displaystyle 10}$

Step-by-step explanation:

Hi there!

Slope-intercept form: $y=mx+b$ where $m$ is the slope and $b$ is the y-intercept (the value of y when x is 0)

1) Determine the slope (m)

$m=\frac{\displaystyle y_2-y_1}{\displaystyle x_2-x_1}$ where two given points are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given points (15,2.2) and (5,1.6):

$m=\frac{\displaystyle 1.6-2.2}{\displaystyle 5-15}\\\\m=\frac{\displaystyle -0.6}{\displaystyle -10}\\\\m=\frac{\displaystyle 0.6}{\displaystyle 10}\\\\m=\frac{\displaystyle 0.3}{\displaystyle 5}\\\\m=\frac{\displaystyle 3}{\displaystyle 50}$

Therefore, the slope of the line is $\frac{\displaystyle 3}{\displaystyle 50}$ . Plug this into $y=mx+b$ :

$y=\frac{\displaystyle 3}{\displaystyle 50}x+b$

2) Determine the y-intercept (b)

$y=\frac{\displaystyle 3}{\displaystyle 50}x+b$

Plug in a given point and solve for b:

$1.6=\frac{\displaystyle 3}{\displaystyle 50}(5)+b\\\\1.6=\frac{\displaystyle 3}{\displaystyle 10}+b\\\\1.6-\frac{\displaystyle 3}{\displaystyle 10}=\frac{\displaystyle 3}{\displaystyle 10}+b-\frac{\displaystyle 3}{\displaystyle 10}\\\\\frac{\displaystyle 13}{\displaystyle 10}=b$