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maria [59]
3 years ago
5

A package of dental floss contains 25 m of floss. How many yards of floss are in the package? If a dental hygienist uses about 1

8 in. of floss for each patient, how many patients can be cleaned with one package of floss?
Mathematics
1 answer:
rusak2 [61]3 years ago
7 0
Twenty five meters converted to yards is 27.34. For the second bit, 18 inches is 1.5 feet so we divide 27.34 by 1.5. He will be able to floss 18 patients. 
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Nimfa-mama [501]
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3 0
3 years ago
A piece of toast came out of the toaster very overcooked.
Nikitich [7]

Answer:

It is a chemical change ⇒ 1st answer

Step-by-step explanation:

* Lets explain the statements to solve the problem

- <u><em>A chemical change</em></u> occurs when a new substance is formed through

 a chemical reaction

- Ex: cooking an egg

- <u><em>Change of reaction</em></u> is the rate of reaction it can be decreases or

  increasing

- <u><em>A phase change</em></u> is a change from one state to another without a

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- Ex: Condensation: the substance changes from a gas to a liquid

- <u><em>A physical change</em></u>, such as a state change or dissolving, but does

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- Ex: Breaking a glass

* Lets solve the problem

- A piece of toast came out of the toaster very overcooked.

∵ It is like the cooking an egg

∴ It is a chemical change

7 0
3 years ago
Is this a piecewise graph function? Check using vertical line test. <br> HELP!
IRINA_888 [86]
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Hope that helped!!!
8 0
3 years ago
One angle measure in an acute triangle is 38°. What could the measure of one of the other angles be?
aivan3 [116]
Acute, Obtuse, Acute, Acute
6 0
3 years ago
Read 2 more answers
Mathematically verify the outlier(s) in the data set using the 1.5 rule.
statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

Q_3=16

The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0
3 years ago
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