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3 years ago

What is the surface area, in centimeters, of a cube with a side length, s, of 1/3 cm?

Mathematics

1 answer:

marta [7]3 years ago

4 0

Answer: 1.3 cm = 3.333333333333333 mm
Formula:
A=6a²

S = 66.66667 mm² = 0.6666667 cm²

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Charles owns a catering business. The amount his 10 most recent clients spent is shown in the histogram below. Why is the graph

Alexxandr [17]

<span>The scales are different on the x-axis and the y-axis.
</span>Therefore, the correct answer choice is:
A. The x-axis scale shows the data is more clustered than it actually is.

5 0

3 years ago

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What is the value of angle marked with x

kipiarov [429]

Answer:

116

Step-by-step explanation:

they are the same bc its a rohmbus

6 0

4 years ago

Find the measures of the angles of the triangle whose vertices are A = (-3,0) , B = (1,3) , and C = (1,-3).A.) The measure of ∠A

alekssr [168]

Answer:

$\theta_{CAB}=128.316$

$\theta_{ABC}=25.842$

$\theta_{BCA}=25.842$

Step-by-step explanation:

A = (-3,0) , B = (1,3) , and C = (1,-3)

We're going to use the distance formula to find the length of the sides:

$r= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}$

$AB= \sqrt{(-3-1)^2+(0-3)^2}=5$

$BC= \sqrt{(1-1)^2+(3-(-3))^2}=9$

$CA= \sqrt{(1-(-3))^2+(-3-0)^2}=5$

we can use the cosine law to find the angle:

it is to be noted that:

the angle CAB is opposite to the BC.

the angle ABC is opposite to the AC.

the angle BCA is opposite to the AB.

to find the CAB, we'll use:

$BC^2 = AB^2+CA^2-(AB)(CA)\cos{\theta_{CAB}}$

$\dfrac{BC^2-(AB^2+CA^2)}{-2(AB)(CA)} =\cos{\theta_{CAB}}$

$\cos{\theta_{CAB}}=\dfrac{9^2-(5^2+5^2)}{-2(5)(5)}$

$\theta_{CAB}=\arccos{-\dfrac{0.62}}$

$\theta_{CAB}=128.316$

Although we can use the same cosine law to find the other angles. but we can use sine law now too since we have one angle!

To find the angle ABC

$\dfrac{\sin{\theta_{ABC}}}{AC}=\dfrac{\sin{CAB}}{BC}$

$\sin{\theta_{ABC}}=AC\left(\dfrac{\sin{CAB}}{BC}\right)$

$\sin{\theta_{ABC}}=5\left(\dfrac{\sin{128.316}}{9}\right)$

$\theta_{ABC}=\arcsin{0.4359}\right)$

$\theta_{ABC}=25.842$

finally, we've seen that the triangle has two equal sides, AB = CA, this is an isosceles triangle. hence the angles ABC and BCA would also be the same.

$\theta_{BCA}=25.842$

this can also be checked using the fact the sum of all angles inside a triangle is 180

$\theta_{ABC}+\theta_{BCA}+\theta_{CAB}=180$

$25.842+128.316+25.842$

$180$

6 0

3 years ago

Read 2 more answers

Write the first five terms of the sequence. an=n2 +2

Alla [95]

Answer:

The first five terms of the given sequence

3, 6, 11, 18, 27

Step-by-step explanation:

It is given that,

an=n² +2

<u>To find the first five terms</u>

a₁ = 1² + 2 = 1 + 2 = 3

a₂ = 2² + 2 = 4 + 2 = 6

a₃ = 3² + 2 = 9 + 2 = 11

a₄ = 4² + 2 = 16 + 8 = 18

a₅ = 5² + 2 = 25 + 2 = 27

Therefore the first five terms of the given sequence

3, 6, 11, 18, 27

4 0

4 years ago

Please look at the attached image. Really need Help!! Who ever find answer first will get brainily.

nadya68 [22]

Answer:

27°

Step-by-step explanation:

XWY and VWY are supplementary

∴ XWY + VWY = 180°

∴ XWY = 180° - VWY

XYW and ZYW are supplementary

∴ XYW + ZYW = 180°

∴ XYW = 180° - ZYW

ΔXWY is a right triangle at X

∴ XWY + XYW = 90°

∴ 180° - VWY + 180° - ZYW = 90°

∴ 180° - 6x + 180° - 4x = 90°

∴ 360° - 10x = 90°

∴ 10x = 270°

∴ x = 27°

7 0

3 years ago

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