Question

10 points i guess

Answer 1

Part A.
Using the Pythagorean theorem,
  PR² = PQ² +QR²
  PR² = (14 ft)² +(6 ft)² = 196 ft² +36 ft² . . . . substitute the given numbers
  PR² = 232 ft² . . . . . . . . . . . . . . . . . . . . . . . .find the sum
  PR = √(232 ft²) ≈ 15.23 ft . . . . . . . . . . . . . take the square root
The length of rod PR is 15.23 ft.

Part B.
Using the Pythagorean theorem,
  PR² = PQ² +QR²
  (16 ft)² = (14 ft)² +QR² . . . . . . . substitute the given numbers
  256 ft² -196 ft² = QR² . . . . . .. subtract 14²
  60 ft² = QR² . . . . . . . . . . . . . . find the sum
  √(60 ft²) = QR ≈ 7.75 ft . . . . . take the square root
The new height QR is about 7.75 ft.