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Rus_ich [418]
3 years ago
7

10 points i guess

Mathematics
1 answer:
Elena-2011 [213]3 years ago
8 0
Part A.
Using the Pythagorean theorem,
  PR² = PQ² +QR²
  PR² = (14 ft)² +(6 ft)² = 196 ft² +36 ft² . . . . substitute the given numbers
  PR² = 232 ft² . . . . . . . . . . . . . . . . . . . . . . . .find the sum
  PR = √(232 ft²) ≈ 15.23 ft . . . . . . . . . . . . . take the square root
The length of rod PR is 15.23 ft.

Part B.
Using the Pythagorean theorem,
  PR² = PQ² +QR²
  (16 ft)² = (14 ft)² +QR² . . . . . . . substitute the given numbers
  256 ft² -196 ft² = QR² . . . . . .. subtract 14²
  60 ft² = QR² . . . . . . . . . . . . . . find the sum
  √(60 ft²) = QR ≈ 7.75 ft . . . . . take the square root
The new height QR is about 7.75 ft.
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Combine like terms,<br><br> 1)c+19-4<br><br> 2)m+12-10
rewona [7]
1) Would be c+15 because you can combine 19-4

2) Would be m+2 because you can combine 12-10
8 0
3 years ago
Read 2 more answers
A rectangular prism has a base of 18 cm by 15 cm and a diagonal of 25 cm. Identify its height. Round to the nearest tenth. HELP
jok3333 [9.3K]

Answer:

8.7 cm

Step-by-step explanation:

You know the relationship between the diagonal of a rectangular prism and the sides as d^2 = x^2 + y^2 + z^2 where x, y and z are the three dimensions of the prism. from your data, 25^2 =18^2 + 15^2 + z^2 or z^2 = 25^2 -18^2 - 15^2. With some simple calculation you getz^2 = 625 - 324 - 225 = 76, or z= 8.7178....

6 0
2 years ago
Given the line y = − 2 5 x + 3, determine if the given line is parallel, perpendicular, or neither. Select the correct answer fo
stiks02 [169]

Answer:

(a) Neither

(a) Perpemdicular

Step-by-step explanation:

Required

Determine the relationship between given lines

(a)

y = -\frac{2}{5}x + 3

and

y = \frac{2}{5}x + 7

An equation written in form: y=mx + b has the slope:

m \to slope

So, in both equations:

m_1 = -\frac{2}{5}

m_2 = \frac{2}{5}

For both lines to be parallel

m_1 = m_2

This is false in this case, because:

-\frac{2}{5} \ne \frac{2}{5}

For both lines to be perpendicular

m_1 * m_2 = -1

This is false in this case, because:

-\frac{2}{5} * \frac{2}{5} \ne -1

(b)

5y + 2x = -10

and

-5x + 2y = 4

Write equations in form: y=mx + b

5y + 2x = -10

5y = -2x +10

Divide by 5

y = -\frac{2}{5}x +2

-5x + 2y = 4

2y = 5x + 4

Divide by 2

y = \frac{5}{2}x + 2

In both equations:

m_1 = -\frac{2}{5}

m_2 = \frac{5}{2}

For both lines to be parallel

m_1 = m_2

This is false in this case, because:

-\frac{2}{5} \ne \frac{5}{2}

For both lines to be perpendicular

m_1 * m_2 = -1

This is true in this case, because:

-\frac{2}{5} * \frac{5}{2} = -1

Cancel out 2 and 5

-1 = -1

6 0
2 years ago
Estimate the sum: 1 3/7 + 3 5/9 + 1/2. Show your work.
NISA [10]
Add 1 3/7 and leave it like that, and then do 9x3=27+5=32 so it’s gonna be 32/9 and then calculate the sum into 691/126 or u can divided more into 5 61/126
8 0
2 years ago
Read 2 more answers
Someone can help me for all the question ?
Dvinal [7]

Answer:

1. 5

2. 3 adult tickets; 2 child tickets

3. See below

Step-by-step explanation:

1.

2 adult tickets cost 2 × $12 = $24

Subtract $24 from $64:

$64 - $24 = $40

Divide $40 by $8:

$40 ÷ $8 = 5

Answer: 5 child tickets

2.

x = number of adult tickets

y = number of child tickets

The total number of tickets is 5, so the first equation is:

x + y = 5

The cost of x adult tickets is 12x. The cost of y child tickets is 8y. The total cost is 12x + 8y. We are told the total cost is $52. The second equation is:

12x + 8y = 52

The system of equation is:

x + y = 5

12x + 8y = 52

Let's solve it by substitution.

Solve the first equation for x.

x = 5 - y

Now we substitute x in the second equation by 5 - y.

12(5 - y) + 8y = 52

Distribute:

60 - 12y + 8y = 52

Combine like terms on the left side:

-4y + 60 = 52

Subtract 60 from both sides:

-4y = -8

Divide both sides by 4.

y = 2

Substitute y = 2 in the first original equation and solve for x.

x + y = 5

x + 2 = 5

x = 3

Answer: 3 adult tickets; 2 child tickets

3.

The customer's claim is incorrect. His sum is $71. 71 is an odd number. Since all ticket prices are even numbers, it is impossible to add only even numbers and get an odd sum. A sum of several amounts of 12 and several amounts of 8 can never equal 71.

We can also show his claim is false using a system of equations.

x + y = 7

12x + 8y = 71

Use substitution.

x = 7 - y

12(7 - y) + 8y = 71

84 - 12y + 8y = 71

84 - 4y = 71

-4y = -13

y = 3.25

This means 3.25 child tickets. The problem states that tickets can be purchased only in whole numbers, so 3.25 tickets cannot be purchased, so the customer's claim is false.

4 0
2 years ago
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