Part A. Using the Pythagorean theorem, PR² = PQ² +QR² PR² = (14 ft)² +(6 ft)² = 196 ft² +36 ft² . . . . substitute the given numbers PR² = 232 ft² . . . . . . . . . . . . . . . . . . . . . . . .find the sum PR = √(232 ft²) ≈ 15.23 ft . . . . . . . . . . . . . take the square root The length of rod PR is 15.23 ft.
Part B. Using the Pythagorean theorem, PR² = PQ² +QR² (16 ft)² = (14 ft)² +QR² . . . . . . . substitute the given numbers 256 ft² -196 ft² = QR² . . . . . .. subtract 14² 60 ft² = QR² . . . . . . . . . . . . . . find the sum √(60 ft²) = QR ≈ 7.75 ft . . . . . take the square root The new height QR is about 7.75 ft.
