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4 years ago

What is the value of x? 6 5 4 7

Mathematics

1 answer:

8_murik_8 [283]4 years ago

6 0

Answer:

Step-by-step explanation:

the answer is 4

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Please help it’s lines

JulijaS [17]

I think the answer is c, 88
Hope this helps :)

6 0

3 years ago

measure a and measure b are vertical angles with measure a = x and measure b = 4x - 30. what is measure a?

Zolol [24]

Answer:

∠a = 10°

Step-by-step explanation:

The measure of ∠a = x

The measure of ∠b = 4x-30

It is also mentioned that the measure a and measure b are vertical angles. We need to find the value of a.

For vertically opposite angles,

∠a = ∠b

x = 4x-30

4x-30=x

Taking like terms together,

4x-x= 30

3x = 30

x = 10

So, the meausre of ∠a is equal to 10°.

3 0

3 years ago

What's the answer to this ? Please help

Liono4ka [1.6K]

You could add them on a number line or count on your fingers.

7 0

4 years ago

Read 2 more answers

there are 8 students on the minibus. five of the students are boys. what fraction of the students or boys?

Hunter-Best [27]

Answer: 5/8

Explanation:

total = 8

boys = 5

fraction = 5/8

3 0

3 years ago

Read 2 more answers

What is the area of the rectangle? shoe your work! do not round anything until the very end and round your final answer to the t

weeeeeb [17]

Answer:

The area of the rectangle is 42 units^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

$A=LW$

In this problem

AB=DC

BC=AD

see the attached figure with letters to better understand the problem

we have that

$L=BC\\W=AB$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have the points

$A(2,-1),B(5,2),C(12,-5),D(9,-8)$

Find out the distance BC

we have

$B(5,2),C(12,-5)$

substitute in the formula

$d=\sqrt{(-5-2)^{2}+(12-5)^{2}}$

$d=\sqrt{(-7)^{2}+(7)^{2}}$

$d_B_C=\sqrt{98}\ units$

Find out the distance AB

we have

$A(2,-1),B(5,2)$

substitute in the formula

$d=\sqrt{(2+1)^{2}+(5-2)^{2}}$

$d=\sqrt{(3)^{2}+(3)^{2}}$

$d_A_B=\sqrt{18}\ units$

Find out the area

$A=(L)(W)$

we have

$L=d_B_C=\sqrt{98}\ units$

$W=d_A_B=\sqrt{18}\ units$

substitute

$A=(\sqrt{98})(\sqrt{18})=42.0\ units^2$

4 0

3 years ago