To Find :
How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% antifreeze.
Solution :
Let, x gallons of 80% antifreeze solution is required :
So,
Therefore, 500 gallons of 80% antifreeze solution is required.
Hey user!!
your answer is here (-:
given :- eleven less than x ( x - 11 ) = twenty three
final answer = x - 11 = 23
correct option is D. x - 11 = 23
if u need the value of x too, then Answer is :-
x - 11 = 23
x = 23 + 11
x = 34
cheers!!
12x+12 step by step below
Answer:
C
Step-by-step explanation:
Use the pythagorean theorem
a² + b² = c²
3² + 4² = c²
9 + 16 = c²
25 = c²
5 = c
