Number of compounding periods is
n=12months×3years=36
I assume that
The total interest=
monthly payment×number of compounding periods - the amount of the present value of an annuity ordinary
I=x×n-pv
Let monthly payment be X
I =Total interest is 1505.82
The present value of an annuity ordinary is
Pv=X [(1-(1+0.09/12)^(-36))÷(0.09/12)]
now plug those in the formula of the total interest above
I=x×n-pv
1505.72=36X-X [(1-(1+0.09/12)^(-36))÷(0.09/12)]
Solve for X using Google calculator to get the monthly payment which is
X=330.72
Check your answer using the interest formula
36×330.72−330.72×((1−(1+0.09
÷12)^(−12×3))÷(0.09÷12))
=1,505.83
Step-by-step explanation:
<em>Look at the picture.</em>
Any pair of choice can be the coordinates of the rotation of the point
W (-3, 4) clockwise.
All points have the same distance from the beginning.
The formula of a distance between the origin and a point (x, y):
W(-3, 4)
(3, -4)
(4, 3)
(-4, -3)
(-4, 3)
3 5/8 or three and five over eight
Answer:
ll and lll only
Step-by-step explanation:
D i believe is the right answer
X = 5
Step-by-step explanation:
78 = 12x+18
-18 -18
60 = 12x
5 = x
