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Dimas [21]
3 years ago
5

A cube has six sides that are numbered 1 to 6 the sides number 1 2 and 5 or green the sides number 3 4 and 6 red what is the pro

bability of rolling the Cube getting a green or even number
Mathematics
1 answer:
Arisa [49]3 years ago
6 0

Answer:

5 / 6

Step-by-step explanation:

The green numbers: 1, 2, 5

The even numbers: 2, 4, 6

Since 2 is an overlap, we'll only count it once.

Total outcomes: 6

Successful outcomes: 5

Probability: 5 / 6

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Whet is 2y+14x-7x+9y
matrenka [14]

Answer:

Step-by-step explanation:

2y + 14x - 7x + 9y

2y + 9y + 14x - 7x

11y + 7x

6 0
2 years ago
Read 2 more answers
Use the quadratic model P(x)=25^2-24x+615 if x equals 8
Lynna [10]
P(x) = 25^2 -24x + 615
P(8) = 25(8 squared) -24(8) +615 = 2023



8 0
3 years ago
Read 2 more answers
A solid has faces that consist of 1 pentagon, 5 congruent equilateral triangles, and 5 congruent squares. The solid has 11 verti
mrs_skeptik [129]
So the solid consist of 1 pentagon, 5 congruent equilateral triangle and 5 congruent squares and has 11 vertices so the number of edges of this solid is 20. I hope you are satisfied with my answer and feel free to ask form more if you have more clarifications.
5 0
3 years ago
Ken started a savings account for school. He plans on spending 10% of the money he earns for leisure activities. He needs to hav
uranmaximum [27]

Answer:

$2,400

Step-by-step explanation:

Ken intends to start a savings account

10% = leisure spending

This means 90% = Expenses for school

Let us represent the amount he must save as : x

Hence in other for him to have $2,160 in his savings account, the amount Ken must earn is calculated as:

90/100 × x = $2,160

Cross Multiply

90x = $2,160 × 100

x = ($2,160 × 100) ÷ 90

x =$2,400

Therefore, the amount Ken has to earn to have the amount needed for school is $2,400

5 0
3 years ago
2 1/3 + 3/7 divided by 2 1/3 x 1 3/7​
oee [108]

Answer: \frac{29}{35}

Step-by-step explanation:

1. Make sure all your denominators are the same, you can do this by multiplying them all by 3 or 7, 2 and 1/3 would become 2 7/21, 3/7 would become 9/21, 2 and 1/3, would become 2 and 7/21, and so on and so forth, leaving us with

2\frac{7}{21}+\frac{9}{21} / 2\frac{7}{21} * 1\frac{9}{21}

2. Now, I would go and solve each side of the equation because we divide them, we can add 2\frac{7}{21} and \frac{9}{21}  together to get  2\frac{16}{21}, because 7 + 9 = 16

2\frac{16}{21} / 2\frac{7}{21} * 1\frac{9}{21}

3. We can do the same thing to the other side, by multiplying the two of them. I'm going to convert both of them to just fractions, 2\frac{7}{21} becomes \frac{49}{21} and 1\frac{9}{21} becomes \frac{30}{21}

\frac{49}{21} *  \frac{30}{21}

Now we can reduce them, and for our first fraction divide the top and bottom by 7, giving us  \frac{7}{3} and the second one by 3, which gives us  \frac{10}{7}

\frac{7}{3} * \frac{10}{7} now we cross divide, where we replace the 7's with ones because they're right across from each other to get  \frac{1}{3} and  \frac{10}{1}, or just 10.

\frac{1}{3} * 10 =  \frac{10}{3}

4. So now we can do a similar thing with the first half of our equation and convert it into a fraction and not a mixed number.

\frac{58}{21} / \frac{10}{3}

Now we multiply divide them, and the easiest way I learned how to do this was by keep the first fraction in its place, and flipping the denominator and numerator of the second, and multiplying them.

so   \frac{58}{21} * \frac{3}{10} which if we multiply both sides, you get \frac{174}{210}

I'll save you some times and simplify it for you, the greatest common factor is 6 so we divide the top and bottom by 6 to get

\frac{29}{35}

4 0
2 years ago
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