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3 years ago

6× - 8 = 2 + 9× -1 equal what

Mathematics

2 answers:

MArishka [77]3 years ago

5 0

The answer is x = -3

Mekhanik [1.2K]3 years ago

3 0

6x-8=2+9x-1
6x -9x= 2-1+8
-3x = 9
x=-3

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Suppose that the functions r and s are defined for all real numbers x as follows.

vlada-n [284]

Step-by-step explanation:

as explained in the other question : when applying an arithmetic operation on functions, you are applying it on the functional expressions.

(r*s)(x) = (x+3)*(2x²) = 2x³ + 6x²

(r-s)(x) = (x+3) - (2x²) = -2x² + x + 3

(r+s)(-1) = (-1 + 3) + (2×(-1)²) = 2 + 2×1 = 4

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2 years ago

Scores turned in by an amateur golfer at a golf course during 2017 and 2018 are as follows. 2017 Season 72 76 77 75 73 71 73 75

Marrrta [24]

The given data are the scores turned in by the amateur golfer, from

which the sample standard deviation can be calculated.

Responses:

The mean and sample standard deviation for the 2017 season are;

Mean = 74

Sample standard deviation ≈ 2.07

The mean and sample standard deviation for the 2018 season are;

Mean = 74

Sample standard deviation ≈ 5.26

<h3>What are the equations for the mean and sample standard deviation?</h3>

The mean is given by the formula;

$\overline x= \mathbf{\dfrac{\sum \left x_i }{N}}}$

N = 8

The mean for the 2017 season is therefore;

$\overline x$ = (72 + 76 + 77 + 75 + 73 + 71 + 73 + 75) ÷ 8 = 74

The sample standard deviation is given by the formula;

$s =\mathbf{\sqrt{\dfrac{\sum \left (x_i-\overline x \right )^{2} }{N -1}}}$

$\sum \left (x_i- \overline x \right )^2$ = 30

N = 8

The sample standard deviation for 2017 season is therefore;

$\sigma =\sqrt{\dfrac{30}{8-1}} \approx \mathbf{2.07}$

The mean and sample standard deviation for the 2017 season are;

Mean = <u>74</u>

Sample standard deviation ≈ <u>2.07</u>

The mean for the 2018 season is found as follows;

$\overline x$ = (62 + 68 + 73 + 75 + 83 + 78 + 83 + 78) ÷ 8 = 74

The sample standard deviation is given by the formula;

$s=\mathbf{\sqrt{\dfrac{\sum \left (x_i-\overline x \right )^{2} }{N - 1}}}$

$\sum \left (x_i- \overline x \right )^2$ = 194

N = 8

The sample standard deviation for 2018 season is therefore;

$Standard \ deviation \ for \ the \ 2018 \ seaon, \sigma =\sqrt{\dfrac{194}{8 - 1}} \approx \mathbf{5.26}$

The mean and sample standard deviation for the 2018 season are;

Mean =<u> 74</u>

Standard deviation ≈<u> 5.26</u>

Learn more about the mean and standard deviation here:

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2 years ago

The library is 6 miles east of the city hall. The mall is 10 miles west of the library. How far and in what direction is the mal

Anestetic [448]

Answer:

I REALLY THINK THE ANSWER IS AAA.

Step-by-step explanation:

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7 0

3 years ago

Manny bought car wash supplies for $48 and 3 buckets for his car wash team. Jen did not buy any car wash supplies but bought 7 b

Bond [772]

Manny
Cost of supplies = $48
Buckets = 3

Jen
buckets= 7

Amount spend by manny = Amount spend by Jen

48+3x= 7x
48 = 7x - 3x
48= 4x
48/4 = x
x= 12
Therefore each bucket costs $12

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4 years ago

9.6.PS-14 A water sprinkler sends water out in a circular pattern. How many feet away from the sprinkler can it spread water if

Naily [24]

<h3>The sprinkler can spread the water 13 feet away from it.</h3>

<em><u>Solution:</u></em>

Given that,

The area formed by the watering pattern is 530.66 square feet

<em><u>The area of circle is given as:</u></em>

$Area = \pi r^2$

Where, "r" is the radius

$530.66 = 3.14 \times r^2\\\\r^2 = \frac{530.66}{3.14}\\\\r^2 = 169\\\\r = 13$

Thus radius is 13 feet

The water is being sent out in circular pattern

The maximum distance at which the water is reaching out will be equal to the radius of the circle as the sprinkler is at the center of the circle.

So the sprinkler can spread the water 13 feet away from it.

7 0

4 years ago