68 is the 22nd term of the following sequence.
<u>Step-by-step explanation:</u>
- The given sequence is with the same common difference between the two consecutive number in the series thus it is said to be the Arithmetic progression ( AP).
- For finding the nth term in the AP we have a formula tn = a + (n-1) × d
- Here a is the first term , n is the number of the term to be founded and d is the common difference between the two consecutive number in the series.
- Thus here tn = 5 + ( 22 - 1 ) × 3.
- On subtracting we get tn = 5 + (21 ) × 3
- On multiplying we get tn = 5 + 63
- After adding we get tn = 68. It is the 22nd term in the given series.
Answer:
The vertex is (3,4)
Step-by-step explanation:
f (x) = x^2 - 6 x + 13
Completing the square
-6/2 = -3 and squaring it = 9
= x^2 -6x +9 +4
= ( x-3) ^2 +4
The equation is now in vertex form
a( x-h) ^2 +k
where the vertex is ( h,k)
The vertex is (3,4)
Answer:
It's not a function.
Step-by-step explanation:
<span>2 square root (x - 5) = 2. 2^2 (x -5) = 2^2. 4(x - 5) = 4. 4x - 20 = 4. 4x = 24. x = 6. This solution is not extraneous, because extraneous solutions emerge from solving the problem but are not actually valid solutions for the initial problem. With rounding, this solution is valid for the initial problem.</span>
