Answer:
f(x) = 4x^2 + 2x - 4.
Step-by-step explanation:
Let the quadratic function be y = f(x) = ax^2 + bx + c.
For the point (-2, 8) ( x = -2 when y = 8) we have:
a(-2)^2 + (-2)b + c = 8
4a - 2b + c = 8 For (0, -4) we have:
0 + 0 + c = -4 so c = -4. For (4, 68) we have:
16a + 4b + c = 68
So we have 2 systems of equations in a and b ( plugging in c = -4):
4a - 2b - 4 = 8
16a + 4b - 4 = 68
4a - 2b = 12
16a + 4b = 72 Multiplying 4a - 2b = 12 by 2 we get:
8a - 4b = 24
Adding the last 2 equations:
24a = 96
a = 4
Now plugging a = 4 and c = -4 in the first equation:
4(4) - 2b - 4 = 8
-2b = 8 - 16 + 4 = -4
b = 2.
The answer it 1. is A.
The answer to 2. is B.
Draw a perpendicular segment from point C to the midpoint of AB. Using the trig sine function sin 80 = x/6 which gives 5.91 for the perpendicular segment. Using the formula A=1/2bh, A= 1/2 x5.91x2sqrt 2 A= 8.4
Answer:
Step-by-step explanation:
Triangle DEF is a right angle triangle.
From the given right angle triangle,
DE represents the hypotenuse of the right angle triangle.
With ∠E as the reference angle,
EF represents the adjacent side of the right angle triangle.
DF represents the opposite side of the right angle triangle.
To determine EF, we would apply
trigonometric ratio
Cos θ = opposite side/hypotenuse. Therefore,
Cos 49 = EF/8
EF = 8Cos49 = 8 × 0.6561
EF = 5.2488
Rounding to the nearest tenth, it becomes 5.2
I believe it's A but it's not exactly clear
