Answer with Step-by-step explanation:
Since we have given
n = 16
a) Describe the sampling distribution for the sample mean.
The sampling distribution of the mean is the population's mean from where the items are sampled.
It would be
b. What is the standard error?
c. For 90% confidence, what is the margin of error?
Degrees of freedom = v - 1= 16-1 = 15
Using t-table, 1.753 cuts 5% level of significance in each tail.
so, Margin of error would be
d. Based on the sample results, create the 90% confidence interval and interpret.
So, 90% confidence interval would be
(103.86,116.136)
Answer:
Kindly check explanation
Step-by-step explanation:
Sale before fundraiser = 32
Sale on the day of fundraiser = c
Cost of each carnation sold = 0.25
(Cost * sale before fundraiser) + cost * sale on day of fundraiser
(0.25 * 32) + 0.25 * c
8 + 0.25c
Or
Total carnation sold * cost per carnation
(sale before fundraiser + sale on day of fundraiser) * cost per carnation
(32 + c) * 0.25
Answer: 0.970 ??
Step-by-step explanation:
Area = side AB * side BC = (5x + 5x + 3)(3x + 92x - 4)
= (10x + 3)(95x - 4) = 950x^2 - 40x + 285x - 12
= 950x^2 + 245x - 12 Answer
This cannot be negative so restriction on x is 950x^2 + 245x > 12
That is x > 0.0421
Answer:
6.7% decrease each day
Step-by-step explanation:
Half life: 10 days
Fraction = 0.5^(t/10)
Where t is the no. of days
Per day: t = 1
0.5^(1/10)
0.9330329815 × 100 = 93.30329917
Decrease of: 100 - 93.30329917
= 6.696700846% each day