Answer: -207
Step-by-step explanation:
Ok im not sure the answer yet so ima work on it at the same time while im explaining it. (The answer will probably be near the end)
We can use the elimination method to eliminate y out. To do that we multiply the first equation by 3.
6x+3y=-12
Now just subtract it from the other equation.
6x+3y=-12
5x+3y=-6
***x=-6***
Usually after doing the elimination method you will have to solve for x but in this case its already solved for you. If you want to find y now you just take the first equation and fill x with -6 and solve for y.
2(-6)+y=-4
-12+y=-4
y=8
Brainliest my answer if it helps you out?
Answer: (b) exactly one plane contains a given line and a point not on the line.
Step-by-step explanation: The basic postulates of geometry are very-well known to all of us. For example-
(i) The intersection of two lines determines a point,
(ii) Two parallel lines give result to a plane,
(iii) A line and a point not on the line determines a plane, etc...
Thus, with the help of the third point, we can easily arrive at the conclusion that a given line and a point not lying on the line is contained in a plane. For example- see the attached figure, AB is a line and P is any point not on the line. They both contained in the plane ABC.
Hence, the correct option is (b).
Step-by-step explanation:
-1/3 a + 4 ≤ 0
3*(-1/3a) + 4*3 ≤ 0*3
-a + 12 ≤ 0
12 ≤ a
12 ⩾a
a⩾12