3 years ago

The center of a circle represented by the equation (x-5)^2+(y+6)^2=4^2 is

Mathematics

2 answers:

Akimi4 [234]3 years ago

8 0

Answer:

(5, -6)

Step-by-step explanation:

andre [41]3 years ago

8 0

Answer:

Step-by-step explanation:

The center of a circle represented by the equation (x-5)^2+(y+6)^2=4^2 is

$x=\sqrt{(-y-10)(y+2)} +5,-\sqrt{(-y-10)(y+2)} +5$

Steps:

(x-5)²+(y+6)²=4²

Rewrite:

(x-5)²+(y-(-6))²=4²

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