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MrRa [10]
4 years ago
10

The center of a circle represented by the equation (x-5)^2+(y+6)^2=4^2 is

Mathematics
2 answers:
Akimi4 [234]4 years ago
8 0

Answer:

(5, -6)

Step-by-step explanation:

andre [41]4 years ago
8 0

Answer:

Step-by-step explanation:

The center of a circle represented by the equation (x-5)^2+(y+6)^2=4^2 is

x=\sqrt{(-y-10)(y+2)} +5,-\sqrt{(-y-10)(y+2)} +5

Steps:

(x-5)²+(y+6)²=4²

Rewrite:

(x-5)²+(y-(-6))²=4²

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Please help!
agasfer [191]
Ok im not sure the answer yet so ima work on it at the same time while im explaining it. (The answer will probably be near the end)

We can use the elimination method to eliminate y out. To do that we multiply the first equation by 3.

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Now just subtract it from the other equation.

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Usually after doing the elimination method you will have to solve for x but in this case its already solved for you. If you want to find y now you just take the first equation and fill x with -6 and solve for y.

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Brainliest my answer if it helps you out?
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