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Elza [17]
4 years ago
6

The parent function f(x) = x2 is translated such that the function g(x) = –x2 + 6x – 5 represents the new function. What is true

about the transformation that was performed?
Mathematics
2 answers:
kkurt [141]4 years ago
8 0

Answer:

1. Translation 3 units to the right;

2. Reflection across the x-axis;

3. Translation 4 units up.

Step-by-step explanation:

First, rewrite the function g(x) in following way:

g(x)=-x^2+6x-5=-(x^2-6x)-5=-(x^2-6x+9-9)-5=-(x-3)^2+9-5=-(x-3)^2+4.

Apply such transformations:

1. Translate the graph of the parent function f(x) 3 units to the right to get the graph of the function f_1(x)=(x-3)^2.

2. Reflect the graph of the function f_1(x) across the x-axis to get the graph of the function f_2(x)=-(x-3)^2.

3. Translate the graph of the function f_2(x) 4 units up to get the graph of the function g(x)=-(x-3)^2+4.

miss Akunina [59]4 years ago
7 0

Answer:

a c d

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

6 0
3 years ago
What mathematical operation is used with translations?<br><br> Answer in complete sentence.
sergejj [24]

Answer:

A multiplication expression that is translated by the direct translation method is shown in Example 11. The expression translates to x × 15. Some multiplication keywords, such as DOUBLE, TWICE, and TRIPLE, translate into a number and the operation of multiplication, as shown in Examples 12 and 13.

Hopefully this helps you!!! ;)

4 0
4 years ago
Read 2 more answers
10 Jobs. 40 jobs
Step2247 [10]
16 days
you cross multiply then divided by 10
7 0
3 years ago
Based on the question
nlexa [21]

From the given table, we have that the lateral limits of f(x) as x -> 3 are different, hence the limit of f(x) does not exist at x = 3.

<h3>What is a limit?</h3>

A limit is given by the value of function f(x) as x tends to a value. For the limit to exist, the lateral limits have to be the same, as follows:

\lim_{x \rightarrow a^-} f(x) = \lim_{x \rightarrow a^+} f(x)

In this problem, we have that:

  • To the left of x = 3, that is, for values that are less than x = 3, f(x) - > -3.
  • To the right of x = 3, that is, for values that are greater than x = 3, f(x) -> 4.

Hence the lateral limits are given as follows:

  • \lim_{x \rightarrow 3^-} f(x) = -3
  • \lim_{x \rightarrow 3^+} f(x) = 4

Since the lateral limits are different, the limit does not exist.

More can be learned about lateral limits at brainly.com/question/26270080

#SPJ1

8 0
2 years ago
Third time posting this question pls help. it's 7 grade maths.pls help i need it​ I give brainlist
garik1379 [7]

Answer:

Step-by-step explanation:

7) m + 6 > 17

   m > 17- 6

8. 500 + p > 1500

9. Let cost of pencil be 'x' and it is 5 less than y

x < y -5

Cost of pencil and ruler is less than $ 30.

x + y < 30

10. r + 5 > 17

         r > 17 - 5

         r > 12

12.She is spending $ x. So, we have to subtract from $10.

10 -x < 5

8 0
3 years ago
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