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2 years ago

Help me with only #10-14 please ????

Mathematics

1 answer:

HACTEHA [7]2 years ago

4 0

#10 - 64°
#11 - 67°
#12 - 42in.
#13 - 45.5in.
#14 - i think it's 133.5 but i'm not sure.

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Which number is greater 30% or 0.03?

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3 years ago

What is the quotient of StartFraction 7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline EndFraction? Star

Arte-miy333 [17]

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3 years ago

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An animal shelter provides a bowl with 1.55 liters of water for 5 cats.

Archy [21]

Answer: The answer is 0.8 liters of water.

Step-by-step explanation: Well there are 5 cats and each cat drinks .15 liters per day. .15x5 = .75 liters of water. 1.55 liters - .75 liters = 0.8 liters left.

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2 years ago

Multiply out and simplify to obtain a minimum sum-of-products boolean expression:

max2010maxim [7]

Answer:

As per the question, we need to convert product of sum into sum of product,

Given:

(A' +B+C')(A'+C'+D)(B'+D'),

At first, we will solve to parenthesis,

= (A'+C'+BD) (B'+D')

As per the Rule, (A+B)(A+C) = A+BC, In our case if we assume X = A'+C', then,

(A' +B+C')(A'+C'+D) = (A'+C'+B)(A'+C'+D) = (A'+C'+BD)

Now,

= (A'+C'+BD) (B'+D') = A'B' + A'D' + C'B' +C'D' +BDB' +BDD"

As we know that AA' = 0, it mean

=A'B'+A'D'+C'B'+C'D'+D*0+B0

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Finally, minimum sum of product boolean expression is

A''B'+A'D'+C'B'+C'D'

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2 years ago

In a study, researchers wanted to measure the effect of alcohol on the hippocampal region, the portion of the brain responsibl

ziro4ka [17]

Answer:

The hippocampus volumes in the alcoholic adolescents are less than the normal volume of 9.02 cm³

Step-by-step explanation:

Let x= the hippocampus volumes in the alcoholic adolescents

We'll conduct a hypothesis test at the 0.01 significance level with

Null hypothesis: x = 9.02 cm³

Alternate hypothesis: x < 9.02 cm³

A sample of 13 alcoholic adolescents gives the parameters

size=N= 13

mean=M= 8.12 cm³

standard deviation= s= 0.8 cm³

According to the sample, with 99% confidence, t statistic for the value X=9.02 can be found using the formula:

t= $\frac{X-M}{\frac{s}{\sqrt{N} } }$ where

M is the sample mean (8.12)
s is the standard deviation of the sample (0.8)
N is the sample size (13)

If we put these numbers in the formula:

t= $\frac{9.02-8.12}{\frac{0.8}{\sqrt{13} } }$ =4.056

One tailed critical value for the sample with 12 degrees of freedom (sample size-1) in 99% confidence level is 2.681.

Since t value (4.056) is bigger than the critical value, we fail to reject the alternate hypothesis, therefore reject the null hypothesis and accept alternate hypothesis.

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2 years ago