Answer:supports the body
facilitates movement
protects internal organs
produces blood cells
stores and releases minerals
Explanation:
The skeletal system in animals helps in their movement, support and to maintain their shape.In humans ,it consists of bones,which works closely with the muscular system.unlike worms and arthropods that have hydrostatic and exoskeleton respectively, humans have endoskeleton.the bones have the following functions;
*It allows the animal move . The skeleton provides support for the body and through the flexible joints ,the body is able to move
*The skeleton protects the internal organs of the body by protecting them against impact.for examples,the ribs protect the lungs and the skull protects the brain.
*Certain cells in the bone produce immune cell and important components of the bone
*The bones also regulate the level of calcium in the blood
Water Vapor and carbon dioxide
Answer:
All of the statements are true.
The X chromosome is one of the two sex chromosomes of humans and some animals (the other sex chromosome is the Y chromosome). Men have a single X chromosome and women two X chromosomes.
Diseases whose gene is localized on the X chromosome are most often transmitted in the X-linked recessive mode; some are transmitted on the dominant mode related to the X.
In this mode of inheritance, the morbid allele behaves like a recessive trait.
Women heterozygotes are not affected but can transmit the disease; they are aid to be conductive of the disease.
The disese is only manifested in male subjects (XY) with only one copy of the gene (hemizygous subjects)
Answer:
Mammals, Mollusks, Roundworms, Arthropods, Flatworms
Explanation:
Exactly 989527/1048576, or approximately 94.37%
Since each trait is carried on a different chromosome, the two traits are independent of each other. Since both parents are heterozygous for the trait, each parent can contribute 1 of a possible 4 combinations of the alleles. So there are 16 possible offspring. I'll use "a", "A", "b", "B" to represent each allele and the possible children are aabb, aabB, aaBb, aaBB, aAbb, aAbB, aABb, aABB, Aabb, AabB, AaBb, AaBB, AAbb, AAbB, AABb, and AABB
Of the above 16 possibilities, there are 7 that are homozygous in an undesired traint and 9 that don't exhibit the undesired trait. So let's first calculate the probability of "what are the chances that all 5 children not exhibiting an undesired trait?" and then subtract that result from 1. So
1-(9/16)^5 = 1 - 59049/1048576 = 989527/1048576 which is approximately 0.943686485 = 94.3686485%
So the answer is exactly 989527/1048576, or approximately 94.37%
