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shtirl [24]
2 years ago
6

If the first step of solving a system of equations by subsistution is to solve one equations for one of the variables, how do ch

oose which variable to solve for??
Pls help I’m so confused?
Mathematics
1 answer:
Nezavi [6.7K]2 years ago
6 0
<span>Choose two equations and use them to eliminate one variable.Choose another pair of equations and use them to eliminate the same variable.<span>Use the resulting pair of equations from steps 1 and 2 to eliminate one of the two remaining variables.</span></span>
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A system of equations is shown below: Equation A: 4c = d − 8 Equation B: c = 5d + 8 Which of the following steps should be perfo
Alchen [17]
<span>Equation A: 4c = d − 8
</span><span>Equation B: c = 5d + 8 
</span>
Multiply Equation A by -5:
Equation A: - 20c = -5d + 40

Equation (1) + (2) :
-19c = 48

Answer: <span>B. Multiply equation A by -5</span>
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3 years ago
Please Help ME!!
koban [17]

Answer:

One way streets make it harder to turn into business, also one way streets often are long and they can throw you off your course

Step-by-step explanation:

I hope this helps

3 0
3 years ago
What is 2/10 plus 43/100
gayaneshka [121]

Answer:

0.63 or 63/100

Step-by-step explanation:

4 0
2 years ago
Consider the points A(5, 3t+2, 2), B(1, 3t, 2), and C(1, 4t, 3). Find the angle ∠ABC given that the dot product of the vectors B
Vilka [71]

Answer:

66.42°

Step-by-step explanation:

<u>Given:</u>

A(5, 3t+2, 2)

B(1, 3t, 2)

C(1, 4t, 3)

BA • BC = 4

Step 1: Find t.

First we have to find vectors BA and BC. We do that by subtracting the coordinates of the initial point from the coordinates of the terminal point.

In vector BA B is the initial point and A is the terminal point.

BA = OA - OB = (5-1, 3t+2-3t, 2-2) = (4, 2, 0)

BC = OC - OB = (1-1, 4t-3t, 3-2) = (0, t, 1)

Now we can find t because we know that BA • BC = 4

BA • BC = 4

To find dot product we calculate the sum of the produts of the corresponding components.

BA • BC = (4)(0) + (2)(t) + (0)(1)

4 = (4)(0) + (2)(t) + (0)(1)

4 = 0 + 2t + 0

4 = 2t

2 = t

t = 2

Now we know that:

BA = (4, 2, 0)

BC = (0, 2, 1)

Step 2: Find the angle ∠ABC.

Dot product: a • b = |a| |b| cos(angle)

BA • BC = 4

|BA| |BC| cos(angle) = 4

To get magnitudes we square each compoment of the vector and sum them together. Then square root.

|BA| = \sqrt{4^2 + 2^2 + 0^2} = \sqrt{20} = 2\sqrt{5}

|BC| = \sqrt{0^2 + 2^2 + 1^2} = \sqrt{5}

2\sqrt{5}\sqrt{5}\cos{(m\angle{ABC})} = 4

10\cos{(m\angle{ABC})} = 4

\cos(m\angle{ABC}) = \frac{4}{10}=\frac{2}{5}

m\angle{ABC} = cos^{-1}{(\frac{2}{5})}

m\angle{ABC} = 66.4218^{\circ}

Rounded to two decimal places:

m\angle{ABC} = 66.42^\circ

3 0
1 year ago
Create a system of equations
Vika [28.1K]

Answer:

Answer: Janet is 16, and David is 11.

Step-by-step explanation:

Let the ages be j and d.

j = d + 5

j + d = 27

Substitute d + 5 for j in the second equation.

d + 5 + d = 27

2d + 5 = 27

2d = 22

d = 11

Substitute 11 for d in the first equation.

j = d + 5

j = 11 + 5

j = 16

Answer: Janet is 16, and David is 11.

6 0
2 years ago
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