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SCORPION-xisa [38]
3 years ago
10

Round 1256 to the nearest tenth

Mathematics
2 answers:
DIA [1.3K]3 years ago
4 0
1260 is the answer.
lorasvet [3.4K]3 years ago
4 0
1256 to the nearest tenth is 1260
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A bank advertises an interest rate of 4% per year, compounded monthly
Darina [25.2K]

Given :

Interest rate , r = 4 %.

To Find :

The APY .

Solution :

APY is given by :

APY=(1+\dfrac{r}{n})^n-1

Here , r is compound interest and n is number of time compounded .

So ,

APY=(1+\dfrac{r}{n})^n-1\\\\APY=(1+\dfrac{4}{12})^{12}-1\\\\APY=30.57\%

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3 years ago
1/2 + 1/3 - 1/4 = I don't know
larisa [96]
Use "PEMDAS"
First we'll add then subtract

\frac{1}{2} + \frac{1}{3} =  \frac{2}{6} +  \frac{2}{6} =  \frac{4}{6}= \frac{2}{3}

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\frac{1}{2} +  \frac{1}{3} -  \frac{1}{4} =  \frac{5}{12}
3 0
3 years ago
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Given that f(x) = 4x - 3 and g(x) 2x-1 divided by 3<br><br> solve for g(f(2))
scZoUnD [109]

Answer:

2nd option = 3 is the answer.

4 0
3 years ago
Short Response
garik1379 [7]

Answer:

(a)2(89x+84)

(b)2(89x+84-x^2\pi)

Step-by-step explanation:

The dimensions of the larger rectangular field are:

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The dimensions of the smaller rectangular soccer field are:

  • Length=5x; Width = 9x.

(a)Area of the part of the field that is outside the soccer field

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=(5x)(9x)+70x+108x+168-5x(9x)

=178x+168

=2(89x+84)

(b)Radius of the Semicircular Fountain =2x

From Part (a),

Area of the larger rectangular field - Area of the Soccer Field=178x+168

Area of the Semicircular Fountain =\dfrac{\pi r^2}{2} =\dfrac{\pi (2x)^2}{2} =\dfrac{4x^2\pi}{2} =2x^2\pi

Area of the Field that does not include the soccer  field or the fountain.

=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain

=178x+168-2x^2\pi\\=2(89x+84-x^2\pi)

8 0
3 years ago
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ab=ab=ab 3679y

Step-by-step explanation:

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