For this case, what you should see is which lines contain point O.
We have then that the lines that contain this point are:
EC
AD
BO
We note that three lines contain point O.
Therefore, three lines intersect at the same point.
Answer:
4. 3
The answer would be prime
Answer:
width = 3.5 m
length = 18 m
Step-by-step explanation:
area = length x width
x is the width then length = 2x + 11
x(2x + 11) = 63
2x^2 + 11x - 63 = 0
The formula to solve a quadratic equation of the form ax^2 + bx + c = 0 is equal to x = [-b +/-√(b^2 - 4ac)]/2a
with a = 2
b = 11
c = -63
substitute in the formula
x = [-11 +/- √(11^2 - 4(2)(-63))]2(2)
x = [-11 +/- √(121 + 504)]/4
x = [-11 +/- √625]/4
x = (-11 +/- 25)/4
x1 = (-11 + 25)/4 = 14/4 = 3.5
x2 = (-11 - 25)/4 = -36/4 = -9
since width can't be a negative number, x is 3.5
length = 2x + 11 = 2(3.5) + 11 = 18
Answer:
Given Rate of interest is r=8%=0.08
Principal Amount is A=5,000
Time is t years
Interest is compounded yearly twice ⟹n=2
Amount =P(1+
n
r
)
nt
=5000×(1+
2
0.08
)
2t
=5,408
(1.0816)
t
=
5000
5408
⟹t=1
I'm not completely sure but this is what I would do.
evaluate <span>(1/ 4)^x - 1 </span>as is. But change the (1 /2)^2x to (2/4)^2x. This way both fractions have the same denominator and in this sense, the same base. The 2/4 base still evaluates into 1/2 so nothing, mathematically, is being broken here.
