How do you turn a interval into an inequality?

1 answer:

3 0

Answer : Interval to Inequality

(a, +∞) x > a "greater than a"

[a, +∞) x ≥ a "greater than or equal to a"

(-∞, a) x < a "less than a"

(-∞, a] x ≤ a "less than or equal to a"

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URGENT!!!

garri49 [273]

Answer:

B: (x - 4)² = 44

Step-by-step explanation:

Start with x^2 - 8x - 10 = 18.

Simplify the constants by adding 10 to both sides: x^2 - 8x - 10 + 10 = 18 + 10.

Then x^2 - 8x = 28.

Now identify the coefficient of x. It is -8.

Take half of this, obtaining -4.

Square this result, obtaining 16.

Add 16, and then subtract 16, to x^2 - 8x:

x^2 - 8x + 16 - 16 = 28.

Add 16 to both sides:

x^2 - 8x + 16 = 28 + 16 = 44

Rewrite x^2 - 8x + 16 as (x - 4)², so that we have:

(x - 4)² = 44. This is in the form (x - p)² = 44, and matches Answer B.

Note: Please use " ^ " to indicate exponentiation: (x - 4)^2 = 44

3 0

3 years ago

5/ 8 inch border closest to 1/ 2 or 1 inch

Triss [41]

$different\ between\ \frac{5}{8}\ and\ \frac{1}{2}=\frac{5}{8}-\frac{1}{2}=\frac{5}{8}-\frac{4}{8}=\frac{1}{8}\\\\different\ between\ 1\ and\ \frac{5}{8}=1-\frac{5}{8}=\frac{8}{8}-\frac{5}{8}=\frac{3}{8}\\\\\frac{1}{8} \ \textless \ \frac{3}{8}\ therefore\ \frac{5}{8}\ is\ closest\ to\ \frac{1}{2}$