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maw [93]
3 years ago
6

Convert 10300000in scientific notation​

Mathematics
2 answers:
ivanzaharov [21]3 years ago
8 0
This should be the correct answer I showed my work in case you need some help understanding the steps to get this answer. Hope this helps! <3

insens350 [35]3 years ago
3 0

Step-by-step explanation:

10300000 = 1,03 * 10⁷

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Find dy/dx if y=(4x^2-5x)^8
musickatia [10]

dy/dx = 8(8x - 5)(4x² - 5x )^ 7

differentiate using the ' chain rule '

dy/dx = 8(4x² - 5x)^ 7 × d/dx (4x² - 5x)

         = 8(4x² - 5x)^ 7  × (8x - 5)

         = 8(8x - 5)(4x² - 5x)^{7}



6 0
3 years ago
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Show work and explain with formulas.
Juli2301 [7.4K]

20 Answer: a₁ = 4

<u>Step-by-step explanation:</u>

a_n=324,\ r=3,\ n=5\\\\a_n=a_1 \cdot r^{n-1}\\\\324=a_1\cdot 3^{5-1}\\\\\dfrac{324}{3^4}=a_1\\\\\dfrac{324}{81}=a_1\\\\\large\boxed{4}=a_1

21 Answer: n = 13

<u>Step-by-step explanation:</u>

a_n=\dfrac{1}{64},\ a_1=64,\ r=\dfrac{1}{2}\\\\a_n=a_1 \cdot r^{n-1}\\\\\dfrac{1}{64}=64\cdot \bigg(\dfrac{1}{2}\bigg)^{n-1}\\\\\dfrac{1}{64\cdot 64}=\bigg(\dfrac{1}{2}\bigg)^{n-1}\\\\\dfrac{1}{2^6\cdot 2^6}=\dfrac{1}{2^{n-1}}\\\\6+6=n-1\\\\\large\boxed{13}=n

22 Answer: n = 5

<u>Step-by-step explanation:</u>

a_n=48,\ a_1=1875\ r=\dfrac{2}{5}\\\\a_n=a_1 \cdot r^{n-1}\\\\48=1875\cdot \bigg(\dfrac{2}{5}\bigg)^{n-1}\\\\\dfrac{48}{1875}=\bigg(\dfrac{2}{5}\bigg)^{n-1}\\\\\dfrac{16}{625}=\bigg(\dfrac{2}{5}\bigg)^{n-1}}\\\\\bigg(\dfrac{2}{5}\bigg)^4=\bigg(\dfrac{2}{5}\bigg)^{n-1}}\\\\4=n-1\\\\\large\boxed{5}=n

6 0
3 years ago
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Number 7 using algorithm
aniked [119]
Sorry it says plus but its times

6 0
3 years ago
Sabendo que "K" satisfaz a equação {2(k-8) + 3(-k+1) = -4k +11} Os valores reais de x que satisfazem a equação 15x² - kx + 1 = 0
erastova [34]

Answer:

D) 1/5 e 1/3

Step-by-step explanation:

You have the following quadratic equation:

15x^2-kx+1=0           (1)

In order to find the values of x that are solution to the equation (1), you first find the solution for k in the following equation:

2(k-8)+3(-k+1)=-4k+11\\\\2k-16-3k+3=-4k+11\\\\2k-3k+4k=11+16-3\\\\3k=24\\\\k=8

Next, you replace the previous value of k in the equation (1) and you use the quadratic formula to find the roots:

15x^2-8x+1=0\\\\x_{1,2}=\frac{-(-8)\pm \sqrt{(-8)^2-4(15)(1)}}{2(15)}\\\\x_{1,2}=\frac{8\pm 2}{30}\\\\x_1=\frac{1}{5}\\\\x_2=\frac{1}{3}

Then, the roots of the equation (1) are

D) 1/5 e 1/3

5 0
3 years ago
Please help me. It’s from my math class
serg [7]

Answer:

he would need about 16 weeks

8 0
3 years ago
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