Which is a safe Internet behavior?
1 answer:
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Answer:
Here is the C function that counts the letters in a string:
int LetterCount(char string[]){ //function to count letters in a string passed as parameter
string[100]; // char type string with size 100
int i, letters; // letter variable stores the count for no. of letters in string
i = letters = 0; //initialize variables i and letters to 0
while (string[i] != '\0') { // loop iterates through the entire string until end of string is reached
if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z') ) { // if condition checks the letters in the string
letters++; } // increments 1 to the count of letters variable each time a letter is found in the string
i++; } //increments value of i to move one character forward in string
printf("Number of Letters in this String = %d", letters); // displays the number of letters in the string
return 0; }
Explanation:
Here the question means that the function should count the letters in a string. So the letters are the alphabets from a to z and A to Z.
Here is the complete program:
#include <stdio.h> // to use input output functions
int LetterCount(char string[]){ // method that takes a character string as parameter and counts the letters in the string
string[100];
int i, letters;
i = letters = 0;
while (string[i] != '\0') {
if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z'))
{letters++; }
i++; }
printf("Number of Alphabets in this String = %d", letters);
return 0;}
int main(){ // start of main function
char string[100]; //declares a char array of string
printf("Please Enter a String : "); //prompts user to enter a string
fgets(string,100,stdin); //get the input string from user
LetterCount(string); } // calls method to count letters in input string
I will explain this function with an example
Lets suppose the user input "abc3" string
string[100] = "abc3"
Now the function has a while loop that while (string[i] != '\0') that checks if string character at i-th position is not '\0' which represents the end of the character string. As value of i = 0 so this means i is positioned at the first character of array i.e. 'a'
At first iteration:
i = 0
letter = 0
if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z') ) if condition checks if the character at i-th position of string is a letter. As the character at 0-th position of string is 'a' which is a letter so this condition evaluates to true. So the statement letter++ inside if condition executes which increments the letter variable to 1. So the value of letter becomes 1. Next statement i++ increments the value of i to 1. So i becomes 1. Hence:
i = 1
letter = 1
At second iteration:
i = 1
letter = 1
if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z') )
if condition checks if the character at i-th position of string is a letter. As the character at 1st position of string is 'b' which is a letter so this condition evaluates to true. So the statements letter++ inside if condition and i++ executes which increments these variables to 1. Hence:
i = 2
letter = 2
At third iteration:
i = 2
letter = 2
if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z') )
if condition checks if the character at i-th position of string is a letter. As the character at 2nd position of string is 'c' which is a letter so this condition evaluates to true. So the statements letter++ inside if condition and i++ executes which increments these variables to 1. Hence:
i = 3
letter = 3
At fourth iteration:
i = 3
letter = 3
if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z') )
if condition checks if the character at i-th position of string is a letter. As the character at 3rd position of string is '3' which is not a letter but a digit so this condition evaluates to false. So the statement letter++ inside if condition does not execute. Now i++ executes which increments this variable to 1. Hence:
i = 4
letter = 3
Now the loop breaks because while (string[i] != '\0') condition valuates to false as it reaches the end of the string.
So the statement: printf("\n Number of Letters in this String = %d", letters); executes which prints the value of letters on the output screen. Hence the output is:
Number of Letters in this String = 3
Answer:
Please check the attachment.
for the assembly language program the jump and move keywords have been used to establish the if else ladder.
Also for the best three marks, we need to store the three theory and two practical marks in an array, and then we can sort it to get the best three marks to find the CA. and then from initial array, we can find the last two practical test parks, and find their average.
Rest of the calculation is as being mentioned in the image. Also, in the image we have 2 practicals. We need to count two instead of three there, and rest is as shown.
Explanation:
The answer does not require any further explanation.
