Answer:
Exact Form:
√
30
Decimal Form:
5.47722557
…
Step-by-step explanation: i would go with D
Answer:
a) 2/3
b) 1/3
Step-by-step explanation:
Let X be the random event that measures the time you will have to wait.
Since time is uniformly distributed between 10 and 10:30 in intervals of 1 minute
P(n < X ≤ n+1) = 1/30 for every minute n=0,1,...29.
a)
P( X > 10) = 1 - P(X ≤ 10) = 1 - 10/30 = 2/3
b)
P(10 < X ≤ 20) = (20-10)/30 = 1/3
Answer:
C
Step-by-step explanation:
Multiply the number of muffins by how much baking powder is in each muffin. That's read as 6/1 × 3/8 which equals 18/8.
Answer:
0.3 is the answer
Step-by-step explanation:
Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way
Step-by-step explanation:
- From a standard deck of cards, one card is drawn. What is the probability that the card is black and a
jack? P(Black and Jack) P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
- A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen
or an ace.
P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13
- WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the probability that they will both be aces?
P(AA) = (4/52)(3/51) = 1/221.
- WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a king?
P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been removed.
- WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the
probability of drawing the first queen which is 4/52.
- The probability of drawing the second queen is also 4/52 and the third is 4/52.
- We multiply these three individual probabilities together to get P(QQQ) =
- P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
- Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
