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saul85 [17]
3 years ago
5

Only 4 true or false questions :3

Mathematics
2 answers:
AlexFokin [52]3 years ago
7 0

1- false

2- true

3- false

4- false

Ira Lisetskai [31]3 years ago
5 0

false

true

false

false

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Solve this equation pls
Aleksandr-060686 [28]

Answer:

{ \rm{y =  \frac{3 \sqrt{x}  + 2x}{ {4x}^{2} } }} \\

• We are gonna use the quotient rule

{ \boxed{ \bf{ \frac{dy}{dx} =  \frac{ {\huge{v} } \frac{du}{dx}   - { \huge{u}} \frac{dv}{dx} }{ {v}^{2} }  }}} \\

  • u is (3√x + 2x)
  • v is 4x²
  • du/dx is 3/2√x
  • dv/dx is 8x

• Therefore:

{ \rm{ \frac{dy}{dx} =  \frac{(4 {x}^{2})( \frac{3}{2 \sqrt{x} }) - (3 \sqrt{x} + 2x)(8x)   }{16 {x}^{4} }  }} \\  \\ { \rm{ \frac{dy}{dx}  =  \frac{(6 {x}^{2})( {x}^{ -  \frac{1}{2} }  ) - (24 {x}^{ \frac{3}{2}  } + 16 {x}^{2} ) }{16 {x}^{4} }  }} \\  \\ { \rm{ \frac{dy}{dx}  =  \frac{ 6 {x}^{ \frac{3}{2} }  -  {24x}^{ \frac{3}{2} }  -  {16x}^{2} }{16 {x}^{4} } }} \\  \\ { \rm{ \frac{dy}{dx}  =  \frac{ - 18 {x}^{ \frac{3}{2}  } - 16 {x}^{2}  }{16 {x}^{4} } }} \\  \\ { \rm{ \frac{dy}{dx}  =  - 2 {x}^{ \frac{3}{2} } (9 + 8 {x}^{ \frac{4}{3} } ) \div 16 {x}^{4} }} \\  \\ { \boxed{ \boxed{ \rm{ \:  \:  \frac{dy}{dx}  =   - \frac{8 \sqrt{ {x}^{ \frac{8}{3} }}  + 9}{8x {}^{ \frac{8}{3} } }  \:  \: }}}}

5 0
2 years ago
Read 2 more answers
1 cup = 8 fluid ounces Does that mean it takes 24 fluid ounces of water to fill any 3 plastic cups?
Pavel [41]
Notice they say Plastic cups. Cups and plastic cups are not the same. Cups are a form of measurement while plastic cups are a container. This is not a true statement. Hope this helps!
3 0
3 years ago
Read 2 more answers
in a round robin tennis tournament involving 7 players, each player will play every other player twice. How many total matches w
baherus [9]
Total number of ways to make a pair:

The first player can be any one of 7 .  For each of those . . .
The opponent can be any one of the remaining 6 .

Total ways to make a pair  =  7 x 6 = 42 ways .

BUT ... every pair can be made in two ways ...  A vs B  or  B vs A .
So 42 'ways' make only (42/2) = 21 different pairs.

If every pair plays 2 matches, then  (21 x 2) = <em><u>42 total matches</u></em> will be played.


Now, is that an elegant solution or what !
8 0
4 years ago
Simplify<br> 4-3[6-2(4-3)]
ikadub [295]

Answer:

<h2>-8</h2>

Step-by-step explanation:

4-3[6-2(4-3)]\\\\Follow\:the\:PEMDAS\:order\:of\:operations\\\\\mathrm{Calculate\:within\:parentheses}\:\left[6-2\left(4-3\right)\right] : 4\\\\=4-3\times\:4\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:3\times\:4\::\quad 12\\=4-12\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:4-12\:\\\\:\quad -8

4 0
3 years ago
P=4<br>q=-2<br>r=-3<br>s=-5<br><br>Solve<br><br><br>s^3 -p^3​
marissa [1.9K]
1. -5^3-4^3
2. -15-64
3. -79
4 0
3 years ago
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