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Evgen [1.6K]
3 years ago
6

What percent of 8 is 32.52?

Mathematics
1 answer:
bonufazy [111]3 years ago
6 0
X8/100=32.52
x8=3252
x=406.5%
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Factor.
Sergio039 [100]

Answer:

4(2x^5+x^2-3)

Step-by-step explanation:

The question is to factorize  8x^5+4x^2-12

<em>What is common from all 3 terms?</em> It is the factor 4, so we take out 4 and write the remaining as "factorized form".

(Work shown below):

8x^5+4x^2-12\\=4(2x^5+x^2-3)

<u>First answer choice is right.</u>

4 0
3 years ago
I need help please and thank you
MrRa [10]

I will show you a way to do 1 and then you pratice with the rest and I'll check it and help you .

This is what I would do to make it easier

1. 7:15 to 11:16 then 12:05 to 6:10

- hours are on the left side-

1 - 7:15 to 8:15

2- 8:15 to 9: 15

3 - 9:15 to 10:15

4 - 10:15 to 11:15

16 - 15 = 1

4 hours and 1 minute

worked :12:05 - 6:10

1- 12:05 to 1:05

2- 1:05 to 2:05

3- 2:05 to 3:05

4 - 3:05 to 4:05

5- 4:05 to 5:05

6- 5:05 to 6:05

10 - 5 = 5

6 hours and 5 mins

4 + 6 = 10 hours

1 + 5 = 6 mins

10 hours and 6 minutes

6 0
3 years ago
Based on the box-and-whisker plot shown below, match each term with the correct value.
VladimirAG [237]

Answer:

Median: 11

Range: 12

25th percentile: 9

75th percentile: 14

Interquartile range: 5

Step-by-step explanation:

✔️Median = the value that lies at the point where the vertical line divides the box into two = 11

✔️Range = max value - min value = 19 - 7 = 12

✔️25th percentile = Q1 = the value at the beginning of the edge of the rectangular box = 9

✔️75th percentile = Q3 = the value at the end of the edge of the box = 14

✔️ Interquartile range = Q3 - Q1 = 14 - 9 = 5

8 0
3 years ago
Tim is buying packages of paper plates and cups. He wants to have equal amounts of each, but plates come 24 per pack, and cups c
liraira [26]
The answer is 8 packages
6 0
3 years ago
If the exponential model f(x)=9(13)x is written with the base e, it will take the form A0ekx. What is A0 and what is k?
nadezda [96]

9 × 13<em>ˣ</em> = 9 × exp(ln(13<em>ˣ </em>))

… = 9 × exp(<em>x</em> ln(13))

… = <em>A</em>₀ × exp(<em>kx</em>)

so that

<em>A</em>₀ = 9

<em>k</em> = ln(13)

3 0
3 years ago
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