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dybincka [34]
2 years ago
8

Write a number using the following clues:

Mathematics
1 answer:
statuscvo [17]2 years ago
6 0

Answer: The answer is 36(multiple possible answers though).

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The differential equation in Example 3 of Section 2.1 is a well-known population model. Suppose the DE is changed to dP dt = P(a
LuckyWell [14K]

Answer:

Decreases

Step-by-step explanation:

We need to determine the integral of the DE;

dP/dt=P(aP-b)

dP=P(aP-b)dt

1/(dP^2-bP)dP=dt

We can solve this by integration by parts on the left side. We expand the fraction 1/P²:

1/(d-b/P)\cdot{P^2} dP

let

u=d-b/P

du/dP=b/P^2

dP=\int\limits {P^2/b} \, du

P=lnu/b

Substitute u in:

P=ln(d-b/P)/b

Therefore the equation is:

ln(d-b/P)/b=t

We simplify:

d-b/P=e^b^t

P=b/(d-e^b^t)

As t increases to infinity P will decrease

6 0
3 years ago
-2y-4=4(y-1) help me find the answer to this
Pepsi [2]
-2y-4=4y-4
2) cancel 4 out on both sides
-2y=4y
3) divide both sides by -2
y=-2y
4) subtract both sides by -2y
y+2y=0
5)3y=0
6) divide by 3

Y=0

3 0
3 years ago
Read 2 more answers
I need help ASAP please
galina1969 [7]
I honestly don’t know






Sorry sweety
6 0
3 years ago
Read 2 more answers
Jake's parents want $100,000 at the end of 40 years. They put their money in an account that yields 4% per year compounded conti
Rudik [331]

Answer:

$ 20,189.65

Step-by-step explanation:

Jake's parents want $100,000 at the end of 40 years. They put their money in an account that yields 4% per year compounded continuously. How much money should jakes parents deposit?

From the above question, we are to find the Principal. The formula for Principal compounded continuously =

P = A / e^rt

Where:

A = Amount after time t = $100,000

r = Interest rate = 4%

t = Time in years = 40 years

First, convert R percent to r a decimal

r = R/100

r = 4%/100

r = 0.04 per year,

Then, solve our equation for P

P = A / e^rt

P = 100,000.00 / e ^(0.04×40)

P = $ 20,189.65

Therefore, the amount Jake's parents should invest = $ 20,189.65

8 0
3 years ago
The mean life of a certain brand of auto batteries is 44 months with a standard deviation of 3 months. Assume that the lives of
alisha [4.7K]

Answer:

99.7%

Step-by-step explanation:

Using the z score formula

z-score is z = (x-μ)/σ

where:

x = raw score

μ = population mean

σ = population standard deviation.

a) for x = raw score = 35

μ = population mean = 44

σ = population standard deviation =3

z = (35 - 44)/3

z = -9/3

z = -3

b) for x = raw score = 53

μ = population mean = 44

σ = population standard deviation =3

z = (53 - 44)/3

z = 9/3

z = 3

We would use the standard normal distribution table to find their probabilities

P(Z<=-3)=0.0013499

P(Z<=+3)=0.99865

So P(-3<=Z<=3)=0.99865 - 0.0013499 = 0.9973

Converting to percentage = 0.9973 × 100 = 99.73%

Therefore, the percentage of auto batteries of this brand that have a life of 35 to 53 months to one decimal place is 99.7%

6 0
3 years ago
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