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Artemon [7]
3 years ago
5

Logarithmic and Exponential Forms of Equations In Exercise, write the logarithmic equation as an exponential equation, or vice v

ersa.
In 12 = 2.4849...
Mathematics
1 answer:
Nata [24]3 years ago
6 0

Answer:

12 = e^{2.4849}

Step-by-step explanation:

For this case we have the following expression:

ln(12) = 2.4849

We need to remember that the natural log and the exponentiation with the base the euler number e are inverse operations, and if we apply exponentiation on both sides of the equation we got this:

e^{ln(12)} = e^{2.4849}

We have the identity operator for this e^{ln(x)}= x

12 = e^{2.4849}

And that would be our final answer for this case.

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3 years ago
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HELP ASAP PLEASE.
nordsb [41]
The range of the primary phone data is 0.28. 
The range of the secondary phone data is 0.73.
The median of the secondary phone data is 0.48 g larger than the median of the primary phone data.

To find the range of the primary phone data, subtract the largest and the smallest values:
0.35 - 0.07 = 0.28

To find the range of the secondary phone data, subtract the largest and the smallest values:
1.18 - 0.45 = 0.73

To find the median of the primary phone data, arrange the data from least to greatest and then find the middle value:
0.07, 0.08, 0.1, 0.1, 0.12, 0.13, 0.14, 0.22, 0.35 - the middle is 0.12

To find the median of the secondary phone data, arrange the data from least to greatest and then find the middle value:
0.45, 0.45, 0.5, 0.6, 0.6, 0.68, 0.82, 0.91, 1.18 - the middle is 0.6

The median of the secondary phone data, 0.6, is 0.6-0.12 larger than the median of the primary phone data; 0.6-0.12 = 0.48
5 0
3 years ago
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