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3 years ago

14

If you made a graph to represent a situation where each avocado costs $0.89, what would be the slope of the line?

1 answer:

tatuchka [14]3 years ago

7 0

Y=.89x
X- amount of avocados
Y- $total of avocados
.89- for each or 89/100 every avocados

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I have a project, im gonna have to teach someone how M and B in the equation y=mx+b affect the equation of the line.

Luba_88 [7]

Y = mix + b would be slope intercept for. your y intercept would be B which is the line that crosses that y intercept your Mx would be a fraction for point slope form like if your slope would be 1 over 2 you would fo up and left twice because of rise over run

8 0

3 years ago

Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

6 0

3 years ago

HELP!!! Need Help With Homework!

Airida [17]

Answer:

<1 and <2

<5 and<6

<4 and <2

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=13%20%5Ctimes%2011%20%3D%3F" id="TexFormula1" title="13 \times 11 =?" alt="13 \times 11 =?" al

gizmo_the_mogwai [7]

13 multiplied by 11 is 143

7 0

3 years ago

If x = 12 and y = 3, what is the value of x - y 2?<br><br> 81<br> 6<br> 3<br> 18

Marianna [84]

Answer:

3

Step-by-step explanation:

x-y^2

Let x = 12 y=3

12 - (3)^2

12 -9

3

7 0

3 years ago