Answer:
y = x² + 2x + 5
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here the vertex = (- 1, 4), thus
y = a(x + 1)² + 4
To find a substitute (0, 5) a point on the graph into the equation
5 = a(0 + 1)² + 4
5 = a + 4 ( subtract 4 from both sides )
a = 1, thus
y = (x + 1)² + 4 ← expand and simplify
= x² + 2x + 1 + 4
= x² + 2x + 5
Answer:
Step-by-step explanation:
Umm well mean you just have to use like terms. start by doing any math until there are no parenthesis, and then you basically just use like terms to solve it. (like if you have 
then you use like terms) I would need specifics to be able to evaluate more, but I hope this helps!
The least squares method will minimize the sum of squares error when describing the equation that best fits the ordered pairs.
Answer:
(1, 2)
Step-by-step explanation:
Given the equation of the lines x + 2y = 5 and 2x - 3y = -4
First we need to make x the subject of the formulas
For x+2y = 5
x = 5 - 2y ... 1
For 2x - 3y = -4
2x = -4+3y
x = (-4+3y)/2 ... 2
Equate 1 and 2
5 - 2y = (-4+3y)/2
2(5-2y) = -4+3y
10 - 4y = -4+3y
-4 -3y = -4-10
-7y = -14
y = 14/7
y = 2
Substitute y = 2 into 1
x = 5 = 2y
x = 5 - 2(2)
x = 5 - 4
x = 1
Hence the point where the lines meet will be at (1, 2)
