Fiona sorted her cds into separate bins. She placed 4 cds in each bin. If she has 160 ,cds how many bins did she feel

PLZ HELP ME ASAP I WILL GIVE THE BRAINLEST!!!

kobusy [5.1K]

b since it is equal and graeter than -7

5 0

3 years ago

After a special medicine is introduced into a petri dish full of bacteria, the number of bacteria remaining in the dish decrease

Digiron [165]

Answer:

the answer is 5.5

5 0

2 years ago

Read 2 more answers

Alexander's dividing oranges into eighths he has 5 oranges.how many eights will be have

Veseljchak [2.6K]

Ther will be 40 eights. Hope this helps!

7 0

3 years ago

Read 2 more answers

According to an article in Newsweek, the natural ratio of girls to boys is 100:105. In China, the birth ratio is 100:114 (46.7%

mojhsa [17]

Answer:

$z=\frac{0.42 -0.467}{\sqrt{\frac{0.467(1-0.467)}{150}}}=-1.154$

$p_v =2*P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of girls born is not significantly different from 0.467

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=63 represent the number of girls born

$\hat p=\frac{63}{150}=0.42$ estimated proportion of girls born

$p_o=0.467$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion if girls is 0.467.:

Null hypothesis: $p=0.467$

Alternative hypothesis: $p \neq 0.467$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.42 -0.467}{\sqrt{\frac{0.467(1-0.467)}{150}}}=-1.154$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of girls born is not significantly different from 0.467

3 0

2 years ago

Find the derivative of F(x)=-x^4+4x^3+ 70 for 0<=x<=3

timofeeve [1]

Answer:

-4x^3 +12x^2 for 0 < x < 3

Step-by-step explanation:

The power rule is appropriate:

(d/dx)x^n = n·x^(n-1)

This is applied to each of the terms.

F'(x) = -(4·x^3) +4(3x^2) +0

F'(x) = -4x^3 +12x^2 . . . . for 0 < x < 3

__

The derivative is not defined at the endpoints of the interval, so F'(x) is only defined on (0, 3), not [0, 3].

8 0

3 years ago