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3 years ago

How much red paint and blue paint do you use to make 20 cups of purple paint?

Mathematics

1 answer:

Iteru [2.4K]3 years ago

7 0

Answer:

To get 20 cups of purple paint, the table shows that we need 8 cups of blue paint and 12 cups of red paint. We can solve the problem using double (or triple) number lines.

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How will adding the value 90 affect the mean and median of the data set 1, 5, 5, 6, 9, 10?

Soloha48 [4]

I believe the answer is B for this question

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3 years ago

Read 2 more answers

What is the 100th term in the following arithmetic number pattern: 2,7,12

ivanzaharov [21]

So the change in between terms is 5 so you would put 5x, then for the first term, which is 2, 5*1(x)(because it's first term) then the difference between 5-2(because it's the 2nd term) So you would plug 100 in for x so 5(100)-3=497. Hope this helped!

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3 years ago

What is the value of expression?

kolezko [41]

$6^{-7}\cdot6^4=6^{-7+4}=6^{-3}$

4 0

3 years ago

Suppose a batch of metal shafts produced in a manufacturing company have a population standard deviation of 1.3 and a mean diame

lbvjy [14]

Answer:

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 208, \sigma = 1.3, n = 60, s = \frac{1.3}{\sqrt{60}} = 0.1678$

What is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Lesser than 208 - 0.1 = 207.9 or greater than 208 + 0.1 = 208.1. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Lesser than 207.9.

pvalue of Z when X = 207.9. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{207.9 - 208}{0.1678}$

$Z = -0.6$

$Z = -0.6$ has a pvalue of 0.2743

2*0.2743 = 0.5486

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

6 0

3 years ago

Consider the function f(x)=x3+3x2â51x+91. What is the remainder if f(x) is divided by (x+9)? Do not include (x+9) in your answer

makkiz [27]

Answer:

The remainder is 64

Step-by-step explanation:

Consider the function $f(x)=x^3+3x^2-51x+91$

Use synthetic division to divide by x+9

x+9=0, x=-9

divide the given f(x) by -9 using synthetic division

-9 1 3 -51 91

0 -9 54 -27

--------------------------------------------------

1 -6 3 64

The remainder is 64

5 0

3 years ago