Rectangle ABCD has vertices A(8,5), B(8,10), C(14,10), and D(14,5). A dilation with a scale factor of 1.2 and centered at the or
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Answer:
<em>True </em>
Step-by-step explanation:
<em>Rate Of Change Of Functions </em>
Given a function y=f(x), the rate of change of f can be computed as the slope of the tangent line in a specific point (by using derivatives), or an approximation by computing the slope of a secant line between two points (a,b) (c,d) that belong to the function. The slope can be calculated with the formula
If this value is calculated with any pair of points and it always results in the same, then the function is linear. If they are different, the function is non-linear.
Let's take the first two points from the table (1,1)(2,4)
Now, we use the second and the third point (2,4) (3,9)
This difference in values of the slope is enough to state the function is non-linear
Answer: True
Change the function into vertex form:
f(x)=x²-10x+16
make a square by (adding half of -10)², which is 25, then subtract it:
f(x)=x²-10x+25-25+16
f(x)=(x-5)²-9
so the vertex is at (5,-9)
another way to do it:
f(x)=x²-10x+16
the vertex is when x=-
, b=-10, a=1 in this case.
x=-(-10/2*1)=5
plug x=5 into the quadratic function, you get f(x)=-9
f(x)=x²-10x+16
make a square by (adding half of -10)², which is 25, then subtract it:
f(x)=x²-10x+25-25+16
f(x)=(x-5)²-9
so the vertex is at (5,-9)
another way to do it:
f(x)=x²-10x+16
the vertex is when x=-
x=-(-10/2*1)=5
plug x=5 into the quadratic function, you get f(x)=-9