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3 years ago

Matthew drove 15 1/2 miles in 1/4 hour what was Matthews average speed

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

3 0

Answer:

Matthews average speed was 62 miles per hour.

Step-by-step explanation:

We know that Matthew drove 15 1/2 miles in 1/4 of an hour. We want to know how many miles Matthew drove every hour. To solve this problem, multiply 15 1/2 by 4.

15 1/2 x 4 = 62

Therefore, Matthews average speed was 62 miles per hour.

Hope this helps! :D

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A town in america has 2400 families and 4200 cars. What is the family : cars ratio?

Dmitry [639]

Answer:

4 : 7

Step-by-step explanation:

No. of families = 2400

No. of cars = 4200

Family : Cars

= 2400 : 4200

= 24 : 42

= 6 x 4 : 6 x 7

= 4 : 7

7 0

3 years ago

Read 2 more answers

There are five students of different ages. Their median age is 13 years A) what are two possibilities for the ages of the three

Levart [38]

A) the median is the middle measurement. Their ages could be 13, 14 and 15.
B) 2 students must be younger than 13
C) Like I said, the median is the middle measurement. If you have a list of numbers, you have to order them and take the middle number.

:) Have a nice day and maybe consider grading this answer brainliest? <3

6 0

3 years ago

A selective university advertises that 96% of its bachelor’s degree graduates have, on graduation day, a professional job offer

OLEGan [10]

Answer:

The probability is $P( p < 0.9207) = 0.0012556$

Step-by-step explanation:

From the question we are told

The population proportion is $p = 0.96$

The sample size is $n = 227$

The number of graduate who had job is k = 209

Generally given that the sample size is large enough (i.e n > 30) then the mean of this sampling distribution is

$\mu_x = p = 0.96$

Generally the standard deviation of this sampling distribution is

$\sigma = \sqrt{\frac{p (1 - p )}{n} }$

=> $\sigma = \sqrt{\frac{0.96 (1 - 0.96 )}{227} }$

=> $\sigma = 0.0130$

Generally the sample proportion is mathematically represented as

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{209}{227}$

=> $\^ p = 0.9207$

Generally probability of obtaining a sample proportion as low as or lower than this, if the university’s claim is true, is mathematically represented as

$P( p < 0.9207) = P( \frac{\^ p - p }{\sigma } < \frac{0.9207 - 0.96}{0.0130 } )$