Answer:
for (char i='a'; i<='e'; i++){
for (char j='a'; j<='e'; j++){
cout << i<< j<< "\n";
}
}
Explanation:
The loop runs all characters from the inner while the outer holds one character, by doing so, a will be matched with a,b,c,... Like wise b,c,d,... and on it goes.
Diana is attaching a brace to a rectangular gate. She will put the brace on the diagonal of the rectangle as shown.
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