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andrey2020 [161]
3 years ago
5

Whats the average cost to put wood floors in a 12 ft x 16 ft room?

Mathematics
1 answer:
Bas_tet [7]3 years ago
8 0
Area in ft sq. × cost per ft sq.
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What is the answer to this?
irina1246 [14]
R^2=(96/2)^2+14^2

r^2=2500

r=√2500

r=50
3 0
3 years ago
I am very confused on this
Alexus [3.1K]
Well first add up all the numbers of marbles (which is 34 in total) and divide it by the number of black marbles.
(which should give you 8/34)
Then simplify the fraction and you should get 4/17
8 0
3 years ago
Read 2 more answers
Question Help
Daniel [21]

\frac{2400}{400}  = 6

each shirt costs $6

\frac{10 - 6}{6}  \times 100 = 66.6666....

The percent markup is about 66.7%

3 0
3 years ago
Tanya is 42 years old. she would like to open aretirement account so she will have half a million dollars in the account when sh
gladu [14]
Let the total amount that Sarah deposited be $x
using the annuity formula:
A=P[((1+r)^n-1)/r]
A=future value
r=rate
n=number of years
from the information given:
A=$500000
r=2.75%
n=65-42=23 years
p=$x
thus plugging our values in the formula we get:
500000=x[((1+0.0275)^(23)-1)/(0.0275)]
500000=31.50x
x=15,872.04883
She deposited 15,873.04883 per year
The monthly deposit will therefore be:
15873.04883/12=$1322.67
7 0
3 years ago
Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2a
Vitek1552 [10]

Answer:

2ab - 6a + 5b - 15

Step-by-step explanation:

Given

2ab - 6a + 5b + \_

Required

Fill in the gap to produce the product of linear expressions

2ab - 6a + 5b + \_

Split to 2

(2ab - 6a) + (5b + \_)

Factorize the first bracket

2a(b - 3) + (5b + \_)

Represent the _ with X

2a(b - 3) + (5b + X)

Factorize the second bracket

2a(b - 3) + 5(b + \frac{X}{5})

To result in a linear expression, then the following condition must be satisfied;

b - 3 = b + \frac{X}{5}

Subtract b from both sides

b - b- 3 = b - b+ \frac{X}{5}

- 3 = \frac{X}{5}

Multiply both sides by 5

- 3 * 5 = \frac{X}{5} * 5

X = -15

Substitute -15 for X in 2a(b - 3) + 5(b + \frac{X}{5})

2a(b - 3) + 5(b + \frac{-15}{5})

2a(b - 3) + 5(b - \frac{15}{5})

2a(b - 3) + 5(b - 3)

(2a + 5)(b - 3)

The two linear expressions are (2a+ 5) and (b - 3)

Their product will result in 2ab - 6a + 5b - 15

<em>Hence, the constant is -15</em>

3 0
3 years ago
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