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3 years ago

Let f (x) = x^2 - 6x - 27

Mathematics

1 answer:

aniked [119]3 years ago

4 0

Answer:

x = 9

x = 3

Step-by-step explanation:

find the roots of x² - 6x - 27 = 0

by factorization (or use any of your favorite methods for solving quadratic equations):

x² - 6x - 27 = 0

(x-9)(x+3) = 0

Hence,

(x-9) = 0 --------> x = 9

(x+3) = 0 --------> x = -3

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3 years ago

Evaluate the Riemann sum for (x) = x3 − 6x, for 0 ≤ x ≤ 3 with six subintervals, taking the sample points, xi, to be the right e

DENIUS [597]

Hello,

Reminders:
$$\sum_{i=1}^{n} i= \dfrac{n(n+1)}{2}$


$
$$ \sum_{i=1}^{n} i^2= \dfrac{n(n+1)}{2}$

$
$$ \sum_{i=1}^{n} i^3= \dfrac{n^2(n+1)^2}{4} $
$

$n=6\\
x_{0}=0\\
x_{n}=3\\
\Delta= \dfrac{x_n-x_0}{n}=0.5\\

$
$x_{i} =0+\Delta*i= \frac{i}{2}$

$\sum_{i=1}^{n}\ \Delta*f(x_{i})=\sum_{i=1}^{6}\ \dfrac{i^3/8-6i}{2}$
$$= \dfrac{1}{2}\sum_{i=1}^{6} (\frac{i^3}{8} -6i)=\dfrac{1}{16}*\frac{(6*7)^2}{4}- \frac{9*7}{2}= -3.9575$

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3 years ago

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