Chicago to KC
d = ??
v = 440 knots
t = t - 3
KC to Chicago
d = ?? But it is the same distance as the givens above.
v = 110 knots
t = t hours
Equation
d = r * t
Solve
Since the distances are the same you can equate the r * t
440 * (t - 3) = 110 * t The numbers would be a lot smaller if you divided both sides by 110
[440 * (t - 3)] / 110 = 110 t / 110
4*(t - 3) = t Remove the brackets.
4t - 12 = t Subtract t from both sides
3t - 12 = 0 Add 12 to both sides
3t = 12 Divide by 3
t = 12/3
t = 4 The time to fly for the slower plane = 4 hours.
Solve for distance.
d = r * t
d = 110knots / hr * 3 hr
d = 440 knots. You should get exactly the same thing for t if you do not divide by sides by 110 knots
440 * (t - 3) = 110*t
440 f - 440 * 3 = 110*t
440t - 1320 = 110t Subtract 110t
440t - 110t - 1320 = 0
330t - 1320 = 0
330t = 1320
t = 1320 / 330
t = 4 Same answer.
