Answer:
frequency of the blue (B) allele ![= 0.4142](https://tex.z-dn.net/?f=%3D%200.4142)
frequency of the red (R) allele ![= 0.5858](https://tex.z-dn.net/?f=%3D%200.5858)
The number of blue plants expected is ![509.652](https://tex.z-dn.net/?f=509.652)
The number of red plants expected is ![1019.304](https://tex.z-dn.net/?f=1019.304)
The anticipated number of violet plants is ![1441.341](https://tex.z-dn.net/?f=1441.341)
Calculated chi square value
Explanation:
Frequency of blue allele is
Frequency of blue allele is equal to sum of frequency of BB and half of frequency of BR
![\frac{302}{2970} + \frac{1}{2} \frac{1857}{2970} \\= 0.1016 + 0.3126\\= 0.4142](https://tex.z-dn.net/?f=%5Cfrac%7B302%7D%7B2970%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%5Cfrac%7B1857%7D%7B2970%7D%20%5C%5C%3D%200.1016%20%2B%200.3126%5C%5C%3D%200.4142)
Frequency of other allele
![1- 0.4142\\= 0.5858](https://tex.z-dn.net/?f=1-%200.4142%5C%5C%3D%200.5858)
Chi Square test
See the attached file
The number of blue plants expected is ![509.652](https://tex.z-dn.net/?f=509.652)
The number of red plants expected is ![1019.304](https://tex.z-dn.net/?f=1019.304)
The anticipated number of violet plants is ![1441.341](https://tex.z-dn.net/?f=1441.341)
Calculated chi square value
Answer:
<h2>A site for the exit of the diphosphates removed from the nucleotide triphosphates.</h2>
Explanation:
Transcription occurs in three steps, i) initiation, ii) elongation, and iii) termination.
Elongation: during elongation , the RNA polymerase add new nucleotides in the growing chain of RNA molecule until it encounter terminator factor, or until it terminate transcription. RNA polymerase has three prominent channels, i) channel for entry of DNA template strand, ii) channel for exit of DNA strand and iii) channel for exit of newly synthesized RNA molecule. There are lots of other enzymes which helps in transcription.
Answer: B. Genetically identical offspring
Explanation:
Its the letter B because its the circulatory system