Ask question

Ask question

All categories

3 years ago

5

What is the answer???

1 answer:

goblinko [34]3 years ago

4 0

$65\º + (3x-10\º) +(2x) = 180\º \\ \\ 65\º+ 3x-10\º +2x = 180\º \\ \\ 3x +2x = 180\º +10\º -65\º\\ \\ 5x = 125\º \\ \\ \\ x= \dfrac{125\º}{5}\qquad \to \boxed{x= 25\º}$

$B= (3x-10\º) \\ \\ B= 3(25\º) -10\º \to \boxed{B= 65\º} \\ \\ C= 2x \º\\ \\ C= 2*(25\º) \to \boxed{C= 50\º}$

You might be interested in

2 x [20 + 8 = (6 + 2)] + 10 x 2

Troyanec [42]

Answer: 7.73 x 2 = 15.46

Step-by-step explanation: 7.73x

4 0

2 years ago

PLEASE HELP I PUT THE PROBLEM AS A PICTURE PLEASE ANSWER WILL GIVE 30 POINTS SHOW WORK

dem82 [27]

Answer:

$\huge\boxed{9}$

Step-by-step explanation:

$\sf (2^8 * 3^{-5} * 6^0)^{-2 } (\frac{3^{-2}}{2^3} )^4*2^{28}$

Rule of exponents $a^0 = 1$ , $1/a^m = a^{-m}$

=> $\sf 2^{8*-2} * 3 ^{-5*-2} * 3 ^{-2}* 2^{-3*4} * 2^{28}$

=> $\sf 2 ^ {-16} * 3^{10} * 3^{-8} * 2 ^{-12}* 2^{28}$

Combining same bases

=> $\sf 2 ^ {-16} * 2 ^{-12}* 2^{28}* 3^{10} * 3^{-8}$

When bases are same , powers are to be added

=> $\sf 2 ^{-16-12+28} * 3^{10-8}$

=> $\sf 2^{-28+28} * 3^2$

=> $\sf 2^0 * 3^2$

=> $\sf 3^2$

=> 9

8 0

3 years ago

This question is really hard for me.Please answer.

GarryVolchara [31]

The correct answer is 13

4 0

3 years ago

Jorge's home run total last month was: 3, 6, 4, 3, 2, 3, 1, 0, 3. What is the mean?

Elena L [17]

Answer:

2.8 if rounded, If not rounded, 2.77

6 0

3 years ago

Read 2 more answers

Write an equation. <br><br>Four more than the product of three and a value x is equal to ninteen

Step2247 [10]

Answer:

see explanation

Step-by-step explanation:

The product of 3 and x is 3x

Four more than this product is 3x + 4, thus

3x + 4 = 19 ← is the equation

5 0

3 years ago

Read 2 more answers