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Evgen [1.6K]
3 years ago
8

 Can someone plz help me What is the surface area of the figure?     A. 408 ft2   B. 458 ft2   C. 545 ft2   D. 720 ft2

Mathematics
2 answers:
AveGali [126]3 years ago
6 0
There are 2 faces 7 x 5

2*(5*7)=2*35=70ft^2

There 2 faces 5 x 5

2*(5*5)=2*25=50ft^2

there are 3 faces 5 x 12

4*(5*12)=4*60=240ft^2

There are 2 faces 7 x 7

2*(7*7)=2*49=98ft^2

Now only we have to sum all of them together

98+240+50+70=458ft^2

kvasek [131]3 years ago
6 0
cuboid : \\ \\ l=12 \ ft , \ \ w = 5 \ ft , \ \ h= 7 \ ft  \\ \\ A = 2wl + 2lh + 2hw  \\ \\A=2\cdot 5\cdot 12 + 2\cdot 12\cdot 7 + 2\cdot 7\cdot 5 = 120+ 168 +70 = 358 \ ft^2 \\ \\ cube: \\ \\ four \ side \  walls : \\ \\ s= 5 \ ft \\ \\ 4  \cdot  s^2  = 4 \cdot 5^ 2 = 4*25 = 100 \ ft^2 \\ \\ surface  \ area \  of \  the  \ figure  : \\ \\ 358 +100 = 458 \ ft^2 \\ \\ Answer : \  B. \  458 ft^ 22

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Step-by-step explanation:

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Given:

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The quadratic equation,

x^2+3x-4

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Then the factor is:

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A line passes through the point (–6, –3) and has a slope of 2/3 . Which point is on the same line?
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Answer:

The point (0, 1) represents the y-intercept.

Hence, the y-intercept (0, 1) is on the same line.

Step-by-step explanation:

We know that the slope-intercept form of the line equation

y = mx+b

where

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  • b is the y-intercept

Given

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  • The slope m = 2/3

Using the point-slope form

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

In our case:

  • m = 2/3
  • (x₁, y₁) = (-6, -3)

substituting the values m = 2/3 and the point (-6, -3)  in the point-slope form

y-y_1=m\left(x-x_1\right)

y-\left(-3\right)=\frac{2}{3}\left(x-\left(-6\right)\right)

y+3=\frac{2}{3}\left(x+6\right)

Subtract 3 from both sides

y+3-3=\frac{2}{3}\left(x+6\right)-3

y=\frac{2}{3}x+4-3

y=\frac{2}{3}x+1

comparing with the slope-intercept form y=mx+b

Here the slope = m = 2/3

Y-intercept b = 1

We know that the value of y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

Given the line

y=\frac{2}{3}x+1

at x = 0, y = 1

Thus, the point (0, 1) represents the y-intercept.

Hence, the y-intercept (0, 1) is on the same line.

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