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2 years ago

Graph the equation using the slope and y-intercept y = -x + 3

Mathematics

2 answers:

docker41 [41]2 years ago

3 0

Answer:

Slope: −1

y-intercept: (0,3)

Step-by-step explanation:

tigry1 [53]2 years ago

3 0

Answer:

Look Below

Step-by-step explanation:

The form for this equation is y = mx + b with m being the slope and b being the y intercept, so -1 is the slope and 3 is the y intercept:

With that we can just use different numbers to make the equation true for different points:

Ex: (1, 2) - - > 2 = -(1) + 3

(2, 1) - - > 1 = -(2) + 3

So now that you have filled points you can graph it

Result:

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Ms. Placencio weighed 153 pounds in 2018. She now weighs 132 pounds. What is the percent change round to the nearest tenths plac

Lera25 [3.4K]

Answer:17.7%

Step-by-step explanation:

132 x

____=_____

153 100

132(100)=153(x)

13200=153x

__________

153 153

x=82.3

100-82.3=17.7

4 0

2 years ago

Joe is using the function E= 1.89x + 2.89y to minimize his expenses when selling

stepan [7]

Answer:

$(d)\ \$13.34$

Step-by-step explanation:

Given

$E = 1.89x + 2.89y$ -- Objective function

Constraints:

$2x + y > 10$

$x + 2y > 8$

$x,y>0$

Required

Minimum value of E

To do this, we apply graphical method

See attachment for plots of $2x + y > 10$ and $x + 2y > 8$

From the attached plot, the point that satisfy $x,y>0$ is:

$(x,y) = (4,2)$

So, we have:

$E = 1.89x + 2.89y$

This gives:

$E =1.89 * 4 + 2.89 * 2$

$E =7.56 + 5.78$

$E =13.34$

7 0

2 years ago

Plz Help (Not really tho). Maath stuff.

Pani-rosa [81]

Answer:

I don't know the answer

7 0

3 years ago

Read 2 more answers

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

9 months ago

31600 rounded to the nearest thousand is what

Zigmanuir [339]

32000 is your answer

hope this helps

4 0

2 years ago